For the Reaction MnO 2 (s) + CO(g)$\rightarrow$ MnO(s) + CO 2 (g)$\Delta$ H = -151 KJ/ Mol rxn

The Answer of For the Reaction MnO 2 (s) + CO(g)$\rightarrow$ MnO(s) + CO 2 (g)$\Delta$ H = -151 KJ/ Mol rxn

For the Reaction MnO 2 (s) + CO(g)$\rightarrow$ MnO(s) + CO 2 (g)$\Delta$ H = -151 KJ/ Mol rxn

The Answer of For the Reaction MnO 2 (s) + CO(g)$\rightarrow$ MnO(s) + CO 2 (g)$\Delta$ H = -151 KJ/ Mol rxn

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For the Reaction
MnO₂(s) + CO(g) $\rightarrow$ MnO(s) + CO₂(g) $\Delta$ H = -151 KJ/ Mol_rxn

Question 18

Multiple Choice

For the reaction
MnO₂(s) + CO(g) $\rightarrow$ MnO(s) + CO₂(g) $\Delta$ H = -151 kJ/ mol_rxn.
How many moles of MnO₂ are required in order for 418 kJ of heat to be released?

A) 1.31 moles
B) 0.246 moles
C) 0.361 moles
D) 2.77 moles
E) none of these

For the Reaction MnO2(s) + CO(g) →\rightarrow→ MnO(s) + CO2(g) Δ\DeltaΔ H = -151 KJ/ Molrxn

Multiple Choice

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For the Reaction
MnO₂(s) + CO(g) $\rightarrow$ MnO(s) + CO₂(g) $\Delta$ H = -151 KJ/ Mol_rxn

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