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Consider the First-Order Homogeneous System of Linear Differential Equations
x(t)=ψ−1(t)C \mathbf{x}(t)=\psi^{-1}(t) \mathbf{C}

Question 22

Multiple Choice

Consider the first-order homogeneous system of linear differential equations
Consider the first-order homogeneous system of linear differential equations Given a fundamental matrix (t) for the system, which of these is the general solution of this system? Here, is an arbitrary constant vector. A) \mathbf{x}(t) =\psi^{-1}(t) \mathbf{C} B) x(t) =\psi(t) \mathbf{C} C) \mathbf{x}(t) =\psi(0) \mathbf{C} D) \mathbf{x}(t) =\psi(t) +C
Given a fundamental matrix Consider the first-order homogeneous system of linear differential equations Given a fundamental matrix (t) for the system, which of these is the general solution of this system? Here, is an arbitrary constant vector. A) \mathbf{x}(t) =\psi^{-1}(t) \mathbf{C} B) x(t) =\psi(t) \mathbf{C} C) \mathbf{x}(t) =\psi(0) \mathbf{C} D) \mathbf{x}(t) =\psi(t) +C (t) for the system, which of these is the general solution of this system?
Here, Consider the first-order homogeneous system of linear differential equations Given a fundamental matrix (t) for the system, which of these is the general solution of this system? Here, is an arbitrary constant vector. A) \mathbf{x}(t) =\psi^{-1}(t) \mathbf{C} B) x(t) =\psi(t) \mathbf{C} C) \mathbf{x}(t) =\psi(0) \mathbf{C} D) \mathbf{x}(t) =\psi(t) +C is an arbitrary constant vector.


A) x(t) =ψ−1(t) C \mathbf{x}(t) =\psi^{-1}(t) \mathbf{C}
B) x(t) =ψ(t) C x(t) =\psi(t) \mathbf{C}
C) x(t) =ψ(0) C \mathbf{x}(t) =\psi(0) \mathbf{C}
D) x(t) =ψ(t) +C \mathbf{x}(t) =\psi(t) +C

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