Consider the Initial Value Problem:

What Is the Solution $y=2 \sin \left(\frac{t}{6}\right)+12 \cos \left(\frac{t}{6}\right)$

Multiple Choice

Consider the initial value problem:

What is the solution of this initial value problem?

A) $y=2 \sin \left(\frac{t}{6}\right) +12 \cos \left(\frac{t}{6}\right)$
B) $y=-12 \cos \left(\frac{t}{6}\right) -2 \sin \left(\frac{t}{6}\right)$
C) $y=2 \cos (6 t) -2 \sin (6 t)$
D) $y=-2 \cos (6 t) -2 \sin (6 t)$