The Voltage Applied to A $0.25-\mathrm{F}$ Capacitor Is Given By $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$

Short Answer

The voltage applied to a $0.25-\mathrm{F}$ capacitor is given by $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$ . Find the current at $3.7 \mathrm{~s}$ .