The Displacement (In $\mathrm{cm}$ ) of a Point Is Given By $s=4 t^{3}-3 \sqrt{1+2 t}$

Short Answer

The displacement (in $\mathrm{cm}$ ) of a point is given by $s=4 t^{3}-3 \sqrt{1+2 t}$ . Find the instantaneous velocity and acceleration at $t=1.5 \mathrm{~s}$ .