The Power $(\mathrm{W})$ Delivered to a Load by A $40 \mathrm{~V}$ Source with Internal Resistance Of

Short Answer

The power $(\mathrm{W})$ delivered to a load by a $40 \mathrm{~V}$ source with internal resistance of $5 \Omega$ is $P=40 i-5 i^{2}$ . What current will give the maximum power?