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For the Reaction Shown, DG \circ = -32 \circ C
N2(g) + 3 H2(g) ? 2

Question 5

Essay

For the reaction shown, DG \circ = -32.8 kJ at 25 \circ C.
N2(g) + 3 H2(g) ? 2 NH3(g)
a. Calculate the equilibrium constant for this reaction at 25°C.
b. Is a mixture of the three gases where
PN2 = 3.5 bar,
PH2 = 1.2 bar, and
PNH3 = 0.22 bar at equilibrium? Justify your answer.
c. What is the value of DG under the conditions of Part b?
d. Compare the answer from Part c with DG°. Explain the difference observed.

Correct Answer:

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a. DG° = -RT lnK
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b. blured image =(0.22)
Since Q ...

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