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For the Reaction (CH3)3CCl(aq)+ OH-(aq)→ (CH3)3COH(aq)+ Cl-(aq)

Question 69

Multiple Choice

For the reaction
(CH3) 3CCl(aq) + OH-(aq) → (CH3) 3COH(aq) + Cl-(aq)
It is found experimentally that doubling the initial concentration of (CH3) 3CCl causes the initial reaction rate to double,but doubling the initial concentration of OH- has no effect on the rate.What is the rate law?


A) Rate = k[(CH3) 3CCl]2[OH-]
B) Rate = k[(CH3) 3CCl][OH-]
C) Rate = k For the reaction (CH<sub>3</sub>) <sub>3</sub>CCl(aq) + OH<sup>-</sup>(aq) → (CH<sub>3</sub>) <sub>3</sub>COH(aq) + Cl<sup>-</sup>(aq) It is found experimentally that doubling the initial concentration of (CH<sub>3</sub>) <sub>3</sub>CCl causes the initial reaction rate to double,but doubling the initial concentration of OH<sup>-</sup> has no effect on the rate.What is the rate law? A) Rate = k[(CH<sub>3</sub>) <sub>3</sub>CCl]<sup>2</sup>[OH<sup>-</sup>] B) Rate = k[(CH<sub>3</sub>) <sub>3</sub>CCl][OH<sup>-</sup>] C) Rate = k D) Rate = k[(CH<sub>3</sub>) <sub>3</sub>COH][Cl<sup>-</sup>] E) Rate = k[(CH<sub>3</sub>) <sub>3</sub>CCl]
D) Rate = k[(CH3) 3COH][Cl-]
E) Rate = k[(CH3) 3CCl]

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