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What Is the Logarithm of the Equilibrium Constant,log K,at 25°C

Question 79

Multiple Choice

What is the logarithm of the equilibrium constant,log K,at 25°C of the voltaic cell constructed from the following two half-reactions?
Fe2+ (aq) + 2e¯ What is the logarithm of the equilibrium constant,log K,at 25°C of the voltaic cell constructed from the following two half-reactions? Fe<sup>2+</sup> (aq) + 2e¯ Fe(s) ; ​E​° = - 0.41V Ag<sup>+</sup>(aq) + e<sup>-</sup> <sup> </sup> Ag(s) ; E° = 0.80 V A) 6.7 B) 40.9 C) 20.3 D) 13.2 E) 67.6Fe(s) ; ​E​° = - 0.41V
Ag+(aq) + e-
What is the logarithm of the equilibrium constant,log K,at 25°C of the voltaic cell constructed from the following two half-reactions? Fe<sup>2+</sup> (aq) + 2e¯ Fe(s) ; ​E​° = - 0.41V Ag<sup>+</sup>(aq) + e<sup>-</sup> <sup> </sup> Ag(s) ; E° = 0.80 V A) 6.7 B) 40.9 C) 20.3 D) 13.2 E) 67.6Ag(s) ; E° = 0.80 V


A) 6.7
B) 40.9
C) 20.3
D) 13.2
E) 67.6

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