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The Equilibrium Constant for the Reaction AgBr(s) Δ\Delta

Question 33

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The equilibrium constant for the reaction AgBr(s)  The equilibrium constant for the reaction AgBr(s)    <sub> </sub> Ag<sup>+</sup>(aq) + Br<sup>- </sup>(aq) is the solubility product constant, K<sub>sp</sub> = 7.7 × 10<sup>-13</sup> at 25°C.Calculate  \Delta G for the reaction when [Ag<sup>+</sup>] = 1.0 × 10<sup>-2</sup> M and [Br<sup>-</sup>] = 1.0 × 10<sup>-3</sup> M.Is the reaction spontaneous or nonspontaneous at these concentrations? A) ( \Delta G = 69.1 kJ/mol, nonspontaneous)  B) ( \Delta G = -69.1 kJ/mol, spontaneous)  C) ( \Delta G = 97.5 kJ/mol, spontaneous)  D) ( \Delta G = 40.6 kJ/mol, nonspontaneous)  E) ( \Delta G = -97.5 kJ/mol, nonspontaneous)  Ag+(aq) + Br- (aq) is the solubility product constant, Ksp = 7.7 × 10-13 at 25°C.Calculate Δ\Delta G for the reaction when [Ag+] = 1.0 × 10-2 M and [Br-] = 1.0 × 10-3 M.Is the reaction spontaneous or nonspontaneous at these concentrations?


A) ( Δ\Delta G = 69.1 kJ/mol, nonspontaneous)
B) ( Δ\Delta G = -69.1 kJ/mol, spontaneous)
C) ( Δ\Delta G = 97.5 kJ/mol, spontaneous)
D) ( Δ\Delta G = 40.6 kJ/mol, nonspontaneous)
E) ( Δ\Delta G = -97.5 kJ/mol, nonspontaneous)

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