For the Reaction CuS(s)+ H 2 (g) H 2 S(g)+ Cu(s)$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g) H 2 S(g)+ Cu(s)$\Delta$

For the Reaction CuS(s)+ H 2 (g) H 2 S(g)+ Cu(s)$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g) H 2 S(g)+ Cu(s)$\Delta$

Solved

For the Reaction CuS(s)+ H₂(g)
H₂S(g)+ Cu(s) $\Delta$

Question 81

Short Answer

For the reaction CuS(s)+ H₂(g) $For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s), \Delta G°f (CuS)= -53.6 kJ/mol \Delta G°f (H2S)= -33.6 kJ/mol \Delta H°f (CuS)= -53.1 kJ/mol \Delta H°f (H2S)= - 20.6 kJ/mol Calculate the value of the equilibrium constant (Kp)for this reaction at 298 K.$
H₂S(g)+ Cu(s),
$\Delta$ G°_f (CuS)= -53.6 kJ/mol
$\Delta$ G°_f (H₂S)= -33.6 kJ/mol
$\Delta$ H°_f (CuS)= -53.1 kJ/mol
$\Delta$ H°_f (H₂S)= - 20.6 kJ/mol
Calculate the value of the equilibrium constant (K_p)for this reaction at 298 K.

For the Reaction CuS(s)+ H2(g) H2S(g)+ Cu(s) Δ\DeltaΔ

Short Answer

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

For the Reaction CuS(s)+ H₂(g)
H₂S(g)+ Cu(s) $\Delta$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge