For the Reaction CuS(s)+ H 2 (g) H 2 S(g)$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g) H 2 S(g)$\Delta$

For the Reaction CuS(s)+ H 2 (g) H 2 S(g)$\Delta$

The Answer of For the Reaction CuS(s)+ H 2 (g) H 2 S(g)$\Delta$

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For the Reaction CuS(s)+ H₂(g)
H₂S(g) $\Delta$

Question 27

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For the reaction CuS(s)+ H₂(g) $For the reaction CuS(s)+ H2(g) H2S(g)+ Cu(s), \Delta G°f (CuS)= -53.6 kJ/mol \Delta G°f (H2S)= -33.6 kJ/mol \Delta H°f (CuS)= -53.1 kJ/mol \Delta H°f (H2S)= -20.6 kJ/mol Calculate \Delta G at 798 K and 1 atm pressure (assume \Delta S° and \Delta H° do not change with temperature).$
H₂S(g)+ Cu(s),
$\Delta$ G°_f (CuS)= -53.6 kJ/mol
$\Delta$ G°_f (H₂S)= -33.6 kJ/mol
$\Delta$ H°_f (CuS)= -53.1 kJ/mol
$\Delta$ H°_f (H₂S)= -20.6 kJ/mol
Calculate $\Delta$ G at 798 K and 1 atm pressure (assume $\Delta$ S°and $\Delta$ H° do not change with temperature).

For the Reaction CuS(s)+ H2(g) H2S(g) Δ\DeltaΔ

Short Answer

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For the Reaction CuS(s)+ H₂(g)
H₂S(g) $\Delta$

Correct Answer:
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