Consider the Reaction CO(g)+ 2H₂(g) CH₃OH(l)at 25°C $\Delta$ G°_f (CO)= -137

Short Answer

Consider the reaction CO(g)+ 2H₂(g) CH₃OH(l)at 25°C.
$\Delta$ G°_f (CO)= -137.3 kJ/mol
$\Delta$ G°_f (CH₃OH)= -166.3 kJ/mol
$\Delta$ H°_f (CO)= -110.5 kJ/mol
$\Delta$ H°_f (CH₃OH)= -238.7 kJ/mol
S°(CO)= 197.9 J/K·mol
S°(CH₃OH)= 126.8 J/K·mol
Calculate $\Delta$ G° at 25°C.