Use Fundamental Identities to Find the Exact Values of the Trigonometric

Multiple Choice

Use fundamental identities to find the exact values of the trigonometric functions for the given conditions. $\csc \theta = 7 \text { and } \cot \theta < 0$

A) $\begin{array} { l } \sin \theta = - \frac { \sqrt { 48 } } { 7 } , \quad \cos \theta = \frac { 1 } { 7 } , \quad \tan \theta = - \frac { 1 } { \sqrt { 48 } } \\\cot \theta = - \sqrt { 48 } , \quad \sec \theta = - \frac { 7 } { \sqrt { 48 } } , \quad \csc \theta = 7\end{array}$
B) $\begin{array} { l } \sin \theta = - \frac { 1 } { 7 } , \quad \cos \theta = \frac { \sqrt { 48 } } { 7 } , \quad \tan \theta = \frac { 1 } { \sqrt { 48 } } \\\cot \theta = \sqrt { 48 } , \quad \sec \theta = \frac { 7 } { \sqrt { 48 } } , \quad \csc \theta = - 7\end{array}$
C) $\begin{array} { c c } \sin \theta = \frac { 1 } { 48 } , \quad \cos \theta = - \frac { \sqrt { 48 } } { 48 } , \quad \tan \theta = - 1 \\\cot \theta = - \sqrt { 48 } , \quad \sec \theta = - \frac { 7 } { \sqrt { 48 } } , \quad \csc \theta = 48\end{array}$
D) $\begin{array} { c } \sin \theta = \frac { 1 } { 7 } , \quad \cos \theta = - \frac { \sqrt { 48 } } { 7 } , \quad \tan \theta = - \frac { 1 } { \sqrt { 48 } } \\\cot \theta = - \sqrt { 48 } , \quad \sec \theta = - \frac { 7 } { \sqrt { 48 } } , \quad \csc \theta = 7\end{array}$
E) $\begin{array} { l } \sin \theta = - \frac { 1 } { 48 } , \quad \cos \theta = \frac { \sqrt { 48 } } { 7 } , \quad \tan \theta = - \frac { 1 } { \sqrt { 48 } } \\\cot \theta = - \sqrt { 48 } , \quad \sec \theta = - \frac { 48 } { \sqrt { 48 } } , \quad \csc \theta = - 7\end{array}$