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Solve the Equation 812x(19)x+2=729(9x)281 ^ { 2 x } \cdot \left( \frac { 1 } { 9 } \right) ^ { x + 2 } = 729 \cdot \left( 9 ^ { x } \right) ^ { - 2 }

Question 1

Multiple Choice

Solve the equation: 812x(19) x+2=729(9x) 281 ^ { 2 x } \cdot \left( \frac { 1 } { 9 } \right) ^ { x + 2 } = 729 \cdot \left( 9 ^ { x } \right) ^ { - 2 }


A) x=0x = 0
B) x=2x = 2
C) x=1x = 1
D) x=1,2x = 1,2
E) x=0,3x = 0,3

Correct Answer:

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