Find $\int \left( \sqrt { x } + \frac { 1 } { \sqrt { x } } \right) d x$

Short Answer

Find: $\int \left( \sqrt { x } + \frac { 1 } { \sqrt { x } } \right) d x$ Enter your answer using standard power function form (a $x ^ { b }$ ), leaving the terms in the order in which they appear in the integral.