Set Up an Integral or Sum of Integrals and Then $x ^ { 2 }$

Multiple Choice

Set up an integral or sum of integrals and then find the area bounded by y = $x ^ { 2 }$ + 3 and y = -5x - 3.

A) $\int _ { - 3 } ^ { - 2 } \left[ \left( x ^ { 2 } + 3 \right) - ( - 5 x - 3 ) \right] d x$ = - $\frac { 1 } { 6 }$
B) $\int _ { 2 } ^ { 3 } \left[ \left( x ^ { 2 } + 3 \right) - ( - 5 x - 3 ) \right] d x$ = $\frac { 149 } { 6 }$
C) $\int _ { - 3 } ^ { - 2 } \left[ ( - 5 x - 3 ) - \left( x ^ { 2 } + 3 \right) \right] d x$ = $\frac { 1 } { 6 }$
D) $\int _ { 2 } ^ { 3 } \left[ ( - 5 x - 3 ) - \left( x ^ { 2 } + 3 \right) \right] d x$ = - $\frac { 149 } { 6 }$
E) none of these