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The Solution of the System of Differential Equations dxdt=6x+5ydydt=5x+4yx(0)=1/3,y(0)=0\begin{array} { l } \frac { d x } { d t } = - 6 x + 5 y \\\frac { d y } { d t } = - 5 x + 4 y \\x ( 0 ) = 1 / 3 , y ( 0 ) = 0\end{array}

Question 18

Multiple Choice

The solution of the system of differential equations dxdt=6x+5ydydt=5x+4yx(0) =1/3,y(0) =0\begin{array} { l } \frac { d x } { d t } = - 6 x + 5 y \\\frac { d y } { d t } = - 5 x + 4 y \\x ( 0 ) = 1 / 3 , y ( 0 ) = 0\end{array} is


A) x=(et5tet) /3,y=5tet/3x = \left( e ^ { t } - 5 t e ^ { t } \right) / 3 , y = - 5 t e ^ { t } / 3
B) x=(ettet) /3,y=tet/3x = \left( e ^ { - t } - t e ^ { - t } \right) / 3 , y = - t e ^ { - t } / 3
C) x=(et+tet) /3,y=tet/3x = \left( e ^ { - t } + t e ^ { - t } \right) / 3 , y = t e ^ { - t } / 3
D) x=(et+5tet) /3,y=5tet/3x = \left( e ^ { - t } + 5 t e ^ { - t } \right) / 3 , y = 5 t e ^ { - t } / 3
E) x=(et5tet) /3,y=5tet/3x = \left( e ^ { - t } - 5 t e ^ { - t } \right) / 3 , y = - 5 t e ^ { - t } / 3

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