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    Exam 16: Solubility and Complex Ion Equilibria
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    What Is the Molar Solubility of Lead(II)chromate in 0\(\times\) 10<sup>-</Sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>)<sub>3</sub><sup>4</sup><sup>-</Sup>,K<sub>f</sub> = 2
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What Is the Molar Solubility of Lead(II)chromate in 0 ×\times× 10-16;for Pb(S2O3)34-,Kf = 2

Question 62

Question 62

Multiple Choice

What is the molar solubility of lead(II) chromate in 0.055 M Na2S2O3? For PbCrO4,Ksp = 2.0 ×\times× 10-16;for Pb(S2O3) 34-,Kf = 2.2 ×\times× 106.


A)  What is the molar solubility of lead(II) chromate in 0.055 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>? For PbCrO<sub>4</sub>,K<sub>sp</sub> = 2.0  \times  10<sup>-</sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>) <sub>3</sub><sup>4</sup><sup>-</sup>,K<sub>f</sub> = 2.2  \times  10<sup>6</sup>. A)    M B)    M C)    M D)    M E)    M M
B)  What is the molar solubility of lead(II) chromate in 0.055 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>? For PbCrO<sub>4</sub>,K<sub>sp</sub> = 2.0  \times  10<sup>-</sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>) <sub>3</sub><sup>4</sup><sup>-</sup>,K<sub>f</sub> = 2.2  \times  10<sup>6</sup>. A)    M B)    M C)    M D)    M E)    M M
C)  What is the molar solubility of lead(II) chromate in 0.055 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>? For PbCrO<sub>4</sub>,K<sub>sp</sub> = 2.0  \times  10<sup>-</sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>) <sub>3</sub><sup>4</sup><sup>-</sup>,K<sub>f</sub> = 2.2  \times  10<sup>6</sup>. A)    M B)    M C)    M D)    M E)    M M
D)  What is the molar solubility of lead(II) chromate in 0.055 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>? For PbCrO<sub>4</sub>,K<sub>sp</sub> = 2.0  \times  10<sup>-</sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>) <sub>3</sub><sup>4</sup><sup>-</sup>,K<sub>f</sub> = 2.2  \times  10<sup>6</sup>. A)    M B)    M C)    M D)    M E)    M M
E)  What is the molar solubility of lead(II) chromate in 0.055 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub>? For PbCrO<sub>4</sub>,K<sub>sp</sub> = 2.0  \times  10<sup>-</sup><sup>16</sup>;for Pb(S<sub>2</sub>O<sub>3</sub>) <sub>3</sub><sup>4</sup><sup>-</sup>,K<sub>f</sub> = 2.2  \times  10<sup>6</sup>. A)    M B)    M C)    M D)    M E)    M M

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