(A) Show That$p ( x ) = \left\{ \begin{array} { l l }
( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \
0 & \text { otherwise }
\end{array} \right.$

Question

(A) Show That$p ( x ) = \left\{ \begin{array} { l l } 
( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \
0 & \text { otherwise }
\end{array} \right.$

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The Answer of (A) Show That$p ( x ) = \left\{ \begin{array} { l l } 
( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \
0 & \text { otherwise }
\end{array} \right.$

(A) Show That $p ( x ) = \left\{ \begin{array} { l l } ( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \\0 & \text { otherwise }\end{array} \right.$

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(A) Show That p(x)={(2−k)x−3+k if x≥10 otherwise p ( x ) = \left\{ \begin{array} { l l } ( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \\0 & \text { otherwise }\end{array} \right.p(x)={(2−k)x−3+k0​ if x≥1 otherwise ​

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(A) Show That $p ( x ) = \left\{ \begin{array} { l l } ( 2 - k ) x ^ { - 3 + k } & \text { if } x \geq 1 \\0 & \text { otherwise }\end{array} \right.$

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