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Find the Surface Area of the Part of the Cone z=(x2+y2)1/2z = \left( x ^ { 2 } + y ^ { 2 } \right) ^ { 1 / 2 }

Question 96

Short Answer

Find the surface area of the part of the cone z=(x2+y2)1/2z = \left( x ^ { 2 } + y ^ { 2 } \right) ^ { 1 / 2 } lying inside the cylinder x2−2x+y2=0x ^ { 2 } - 2 x + y ^ { 2 } = 0 .

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