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The Henry's Law Constant (Mol/L · Atm) for Carbon Dioxide

Question 107

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The Henry's law constant (mol/L · atm) for carbon dioxide dissolving in water is 3.50 102 mol/(L atm) at 20C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397.


A) 1.4 The Henry's law constant (mol/L · atm)  for carbon dioxide dissolving in water is 3.50 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> mol/(L atm)  at 20<font face= symbol ></font>C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397. A) 1.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M B) 3.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M C) 2.7   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M D) 8.2   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M E) 8.6   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M 103 M
B) 3.4 The Henry's law constant (mol/L · atm)  for carbon dioxide dissolving in water is 3.50 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> mol/(L atm)  at 20<font face= symbol ></font>C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397. A) 1.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M B) 3.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M C) 2.7   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M D) 8.2   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M E) 8.6   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M 103 M
C) 2.7 The Henry's law constant (mol/L · atm)  for carbon dioxide dissolving in water is 3.50 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> mol/(L atm)  at 20<font face= symbol ></font>C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397. A) 1.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M B) 3.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M C) 2.7   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M D) 8.2   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M E) 8.6   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M 102 M
D) 8.2 The Henry's law constant (mol/L · atm)  for carbon dioxide dissolving in water is 3.50 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> mol/(L atm)  at 20<font face= symbol ></font>C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397. A) 1.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M B) 3.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M C) 2.7   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M D) 8.2   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M E) 8.6   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M 102 M
E) 8.6 The Henry's law constant (mol/L · atm)  for carbon dioxide dissolving in water is 3.50 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> mol/(L atm)  at 20<font face= symbol ></font>C. Calculate the molar concentration of carbon dioxide in a soda can where the air pressure is 2.45 atm. The mole fraction of carbon dioxide in air is 0.0397. A) 1.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M B) 3.4   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>3</sup> M C) 2.7   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M D) 8.2   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M E) 8.6   <font face= symbol ></font>10<font face= symbol ><sup></sup></font><sup>2</sup> M 102 M

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