Essay
A consultant has been brought in to a manufacturing plant to help apply six sigma principles.Her first task is to work on the production of rubber balls.The upper and lower spec limits are 21 and 19 cm respectively.The consultant takes ten samples of size five and computes the sample standard deviation to be .7 cm and the sample mean to be 19.89 cm.Compute 
and 
for the process.Give the consultant advice on what to do with the process based on your findings.
Correct Answer:
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= (21 - 19)/(6∗.7)= .476 = min ( (21 -...View Answer
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Correct Answer:
Verified
= (21 - 19)/(6∗.7)= .476 = min ( (21 -...View Answer
Unlock this answer now
Get Access to more Verified Answers free of charge
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