Exam 6: The Normal Distribution and Other Continuous Distributions
Exam 1: Defining and Collecting Data204 Questions
Exam 2: Organizing and Visualizing Variables185 Questions
Exam 3: Numerical Descriptive Measures167 Questions
Exam 4: Basic Probability163 Questions
Exam 5: Discrete Probability Distributions216 Questions
Exam 6: The Normal Distribution and Other Continuous Distributions187 Questions
Exam 7: Sampling Distributions129 Questions
Exam 8: Confidence Interval Estimation189 Questions
Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests185 Questions
Exam 10: Two-Sample Tests212 Questions
Exam 11: Analysis of Variance210 Questions
Exam 12: Chi-Square and Nonparametric Tests175 Questions
Exam 13: Simple Linear Regression210 Questions
Exam 14: Introduction to Multiple Regression256 Questions
Exam 15: Multiple Regression Model Building67 Questions
Exam 16: Time-Series Forecasting168 Questions
Exam 17: Business Analytics113 Questions
Exam 18: A Roadmap for Analyzing Data325 Questions
Exam 19: Statistical Applications in Quality Management158 Questions
Exam 20: Decision Making123 Questions
Exam 21: Getting Started: Important Things to Learn First35 Questions
Exam 22: Binomial Distribution and Normal Approximation230 Questions
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A company that sells annuities must base the annual payout on the probability distribution of the length of life of the participants in the plan.Suppose the probability distribution of the lifetimes of the participants is approximately a normal distribution with a mean of 68 years and a standard deviation of 3.5 years.Find the age at which payments have ceased for approximately 86% of the plan participants.
(Short Answer)
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The interval between patients arriving at an outpatient clinic follows an exponential distribution at a rate of 1.5 patients per hour.What is the probability that a randomly chosen arrival to be less than 10 minutes?
(Short Answer)
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.The probability that Z is less than -2.20 is .
(Short Answer)
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A company that receives most of its orders by telephone conducted a study to determine how long customers were willing to wait on hold before ordering a product.The length of waiting time was found to be a variable best approximated by an exponential distribution with a mean length of waiting time equal to 3 minutes .What proportion of customers having to hold more than 4.5 minutes will hang up before placing an order?
(Multiple Choice)
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The interval between patients arriving at an outpatient clinic follows an exponential distribution with mean 15 minutes.What is the probability that a randomly chosen arrival to be more than 18 minutes?
(Short Answer)
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You were told that the amount of time elapsed between consecutive trades on a foreign stock exchange market followed a normal distribution with a mean of 15 seconds.You were also told that the probability that the time elapsed between two consecutive trades to fall between 16 to 17 seconds was 13%.The probability that the time elapsed between two consecutive trades would fall below 13 seconds was 7%.What is the probability that the time elapsed between two consecutive trades will be between 15 and 16 seconds?
(Short Answer)
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The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and a standard deviation of 2 minutes.The probability is
that a product is assembled in between 10 and 12 minutes.
(Short Answer)
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The interval between patients arriving at an outpatient clinic follows an exponential distribution at a rate of 1 patient per hour.What is the probability that a randomly chosen arrival to be less than 20 minutes?
(Short Answer)
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The value of the cumulative standardized normal distribution at Z is 0.8770.The value of Z is
(Multiple Choice)
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Let X represent the amount of time until the next student will arrive in the library parking lot at the university.If we know that the distribution of arrival time can be modeled using an exponential distribution with a mean of 4 minutes (i.e.the mean number of arrivals is 1/4 per minute),find the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot.
(Multiple Choice)
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You were told that the amount of time elapsed between consecutive trades on a foreign stock exchange market followed a normal distribution with a mean of 15 seconds.You were also told that the probability that the time elapsed between two consecutive trades to fall between 16 to 17 seconds was 13%.The probability that the time elapsed between two consecutive trades would fall below 13 seconds was 7%.The probability is 80% that the time elapsed will be longer than how many seconds?
(Short Answer)
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SCENARIO 6-2
John has two jobs.For daytime work at a jewelry store he is paid $15,000 per month,plus a commission.His monthly commission is normally distributed with mean $10,000 and standard deviation $2000.At night he works occasionally as a waiter,for which his monthly income is normally distributed with mean $1,000 and standard deviation $300.John's income levels from these two sources are independent of each other.
-Referring to Scenario 6-2,for a given month,what is the probability that John's commission from the jewelry store is between $11,000 and $12,000?
(Short Answer)
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SCENARIO 6-5
A company producing orange juice buys all its oranges from a large orange orchard.The amount of juice that can be squeezed from each of these oranges is approximately normally distributed with a mean of 4.7 ounces and some unknown standard deviation.The company's production manager knows that the probability is 30.85% that a randomly selected orange will contain less than 4.5 ounces of juice.Also,the probability is 10.56% that a randomly selected orange will contain more than 5.2 ounces of juice.Answer the following questions without the help of a calculator,statistical software or statistical table.
-Referring to Scenario 6-5,what is the probability that a randomly selected orange will contain more than 4.2 ounces of juices?
(Short Answer)
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The "middle spread," that is the middle 50% of the normal distribution,is equal to one standard deviation.
(True/False)
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SCENARIO 6-5
A company producing orange juice buys all its oranges from a large orange orchard.The amount of juice that can be squeezed from each of these oranges is approximately normally distributed with a mean of 4.7 ounces and some unknown standard deviation.The company's production manager knows that the probability is 30.85% that a randomly selected orange will contain less than 4.5 ounces of juice.Also,the probability is 10.56% that a randomly selected orange will contain more than 5.2 ounces of juice.Answer the following questions without the help of a calculator,statistical software or statistical table.
-Referring to Scenario 6-5,what is the probability that a randomly selected orange will contain at least 4.9 ounces of juices?
(Short Answer)
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.The probability that Z is between -2.89 and -1.03 is .
(Short Answer)
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Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1.The probability that Z values are larger than is 0.3483.
(Short Answer)
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If there is an order for 60,000 ball bearings and it states the bearing diameters must be between
5.96 and 6.04 mm,how many should the manager manufacture?
(Short Answer)
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You were told that the amount of time elapsed between consecutive trades on a foreign stock exchange market followed a normal distribution with a mean of 15 seconds.You were also told that the probability that the time elapsed between two consecutive trades to fall between 16 to 17 seconds was 13%.The probability that the time elapsed between two consecutive trades would fall below 13 seconds was 7%.The middle 86% of the time elapsed will fall between which two numbers?
(Short Answer)
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For some value of Z,the value of the cumulative standardized normal distribution is 0.2090.The value of Z is
(Multiple Choice)
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