Exam 11: Analytic Geometry

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Determine the two equations necessary to graph the horizontal parabola using a graphing calculator. - x=5y27y+5x = 5 y ^ { 2 } - 7 y + 5

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Give the focus, directrix, and axis for the parabola. - (x+2)2=24(y5)( x + 2 ) ^ { 2 } = - 24 ( y - 5 )

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Give the focus, directrix, and axis for the parabola. - 136x2=y- \frac { 1 } { 36 } x ^ { 2 } = y

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Graph the hyperbola. - 16x29y2=14416 x ^ { 2 } - 9 y ^ { 2 } = 144  Graph the hyperbola. - 16 x ^ { 2 } - 9 y ^ { 2 } = 144

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Find the eccentricity e of the ellipse. -A rectangular board is 19 by 20 units. The foci of an ellipse are located to produce the largest area. A string is connected to the foci and pulled taut by a pencil in order to draw the ellipse. Find the Length of the string.

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Match the equation of the parabola with the appropriate description. - y=2+4xx2y = 2 + 4 x - x ^ { 2 }

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Graph the hyperbola. - 36y216x2=57636 y^{2}-16 x^{2}=576  Graph the hyperbola. - 36 y^{2}-16 x^{2}=576

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Graph the ellipse. - 4x2+64y2=2564 x ^ { 2 } + 64 y ^ { 2 } = 256  Graph the ellipse. - 4 x ^ { 2 } + 64 y ^ { 2 } = 256

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Graph the hyperbola. - (y2)24(x+1)236=1\frac { ( y - 2 ) ^ { 2 } } { 4 } - \frac { ( x + 1 ) ^ { 2 } } { 36 } = 1  Graph the hyperbola. - \frac { ( y - 2 ) ^ { 2 } } { 4 } - \frac { ( x + 1 ) ^ { 2 } } { 36 } = 1

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Find the eccentricity e of the hyperbola. - x216y2=1x ^ { 2 } - 16 y ^ { 2 } = 1

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Match the equation of the ellipse with the appropriate description. - 36x2=29169y236 x ^ { 2 } = 2916 - 9 y ^ { 2 }

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Give the focus, directrix, and axis for the parabola. - (x+9)2=8y( x + 9 ) ^ { 2 } = 8 y

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Provide an appropriate response. -Explain the differences between an ellipse and a hyperbola. Both definitions emphasize distance, but how is distance used differently in these two definitions?

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Match the equation of the ellipse with the appropriate description. - x249=1y225\frac { x ^ { 2 } } { 49 } = 1 - \frac { y ^ { 2 } } { 25 }

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Provide an appropriate response. -  Discuss the graph of the equation x2a2+y2b2=1 if a=b\text { Discuss the graph of the equation } \frac { x ^ { 2 } } { a ^ { 2 } } + \frac { y ^ { 2 } } { b ^ { 2 } } = 1 \text { if } a = b \text {. }

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Write an equation for the hyperbola. -vertices at (1,2)( 1 , - 2 ) and (9,2)( 9 , - 2 ) , passing through the point (5,16)( - 5,16 )

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Identify the type of graph. - x211=1+y25\frac { x ^ { 2 } } { 11 } = 1 + \frac { y ^ { 2 } } { 5 }

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