Exam 11: Analytic Geometry

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Give the focus, directrix, and axis for the parabola. -A cross-section of an irrigation canal is a parabola. If the surface of the water is 48 ft wide and the canal is 7 ft deep at the center, how deep is it 24 ft from the edge?

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Identify the equation as a parabola, circle, ellipse, or hyperbola. - 5x2y=145 x ^ { 2 } - y = 14

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Provide an appropriate response. -Explain why the graph of a hyperbola does not satisfy the conditions for the graph of a function.

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Write an equation for the hyperbola. -vertices at (5,0),(5,0)( 5,0 ) , ( - 5,0 ) ; foci at (9,0),(9,0)( 9,0 ) , ( - 9,0 )

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Find the center, foci, and asymptotes of the hyperbola. - (y2)2144(x4)281=1\frac { ( y - 2 ) ^ { 2 } } { 144 } - \frac { ( x - 4 ) ^ { 2 } } { 81 } = 1

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Match the equation of the parabola with the appropriate description. - x=2y26y+5x = 2 y ^ { 2 } - 6 y + 5

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Find the eccentricity of the conic section shown in the graph. -When a certain satellite was at a maximum distance of 59.5×10659.5 \times 10 ^ { 6 } m from Earth's center, it had a velocity of 4228 m per sec. Determine the shape of its trajectory.

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Provide an appropriate response. -The hyperbola with equation x281y236=1 opens up and down. \frac { x ^ { 2 } } { 81 } - \frac { y ^ { 2 } } { 36 } = 1 \text { opens up and down. }

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Identify the type of graph. - (x+6)2+(y3)2+11=0( x + 6 ) ^ { 2 } + ( y - 3 ) ^ { 2 } + 11 = 0

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Give the focus, directrix, and axis for the parabola. -A projectile is thrown upward so that its distance above the ground after t seconds is h=14t2+476t\mathrm { h } = - 14 \mathrm { t } ^ { 2 } + 476 \mathrm { t } After how many seconds does it reach its maximum height?

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Provide an appropriate response. -Explain in your own words how you can tell from the equation whether the branches of a hyperbola open up and down or left and right.

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Identify the equation as a parabola, circle, ellipse, or hyperbola. - 14y=4(x+4)214 y = 4 ( x + 4 ) ^ { 2 }

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Identify the type of graph. - (x7)23+(y3)27=0\frac { ( x - 7 ) ^ { 2 } } { 3 } + \frac { ( y - 3 ) ^ { 2 } } { 7 } = 0

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Determine the two equations necessary to graph the horizontal parabola using a graphing calculator. - x+3=(y+6)2x + 3 = ( y + 6 ) ^ { 2 }

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Give the focus, directrix, and axis for the parabola. - x=10y2x = 10 y ^ { 2 }

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Find the eccentricity of the conic section shown in the graph. - x=21x = - 21  Find the eccentricity of the conic section shown in the graph. - x = - 21

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Graph the ellipse. - x29+y225=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 25 } = 1  Graph the ellipse. - \frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 25 } = 1

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Provide an appropriate response. -Why is it not possible to choose h and k, neither zero, so the parabola f(x)=a(xh)2+kf ( x ) = a ( x - h ) ^ { 2 } + k has its vertex at the origin?

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Match the equation of the ellipse with the appropriate description. - 49y2=49004x249 y ^ { 2 } = 4900 - 4 x ^ { 2 }

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Graph the conic section. - 25y216x2=40025 y^{2}-16 x^{2}=400  Graph the conic section. - 25 y^{2}-16 x^{2}=400

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