Exam 12: Exponential and Logarithmic Functions

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Write as an exponential equation. - log33=12\log _ { 3 } \sqrt { 3 } = \frac { 1 } { 2 }

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Approximate the logarithm to four decimal places using the change of base formula. - log215\log _ { 2 } \frac { 1 } { 5 }

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Solve the equation. Give an exact solution. - 62x=2.26 ^ { 2 x } = 2.2

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Find f(x) and g(x) so that the given function h(x) = (f ° g)(x). - h(x)=5x+7h ( x ) = \frac { 5 } { x + 7 }

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Solve the equation for x. Give an exact solution. - log3x=8\log 3 x = - 8

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Provide an appropriate response. -Solve 6x2=1366 ^ { x - 2 } = \frac { 1 } { 36 } for xx . Give an exact solution.

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Write the function F(x) as a composition of f, g, or h. - f(x)=-2g(x)=-6xh(x)= F(x)=36-2

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Find the inverse of the one-to-one function. - f(x)=6x+9f ( x ) = 6 x + 9

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Graph the exponential function. - y=(13)xy = - \left( \frac { 1 } { 3 } \right) ^ { x }  Graph the exponential function. - y = - \left( \frac { 1 } { 3 } \right) ^ { x }

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Solve the equation. - log4(x5)=4\log _ { 4 } ( x - 5 ) = 4

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Write the expression as sums or differences of multiples of logarithms. - logy9x2\log _ { y } \frac { 9 x } { 2 }

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Solve the logarithmic equation for x. Give an exact solution - log8(3x2)=2\log _ { 8 } ( 3 x - 2 ) = 2

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Find the exact value. - lne2.2\ln \mathrm { e } ^ { 2.2 }

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Determine whether the function is one-to-one. If it is one-to-one find an equation or a set of ordered pairs that defines the inverse function of the given function. - f={(0,0),(1,1),(2,8)}\mathrm { f } = \{ ( 0,0 ) , ( 1,1 ) , ( - 2,8 ) \}

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Determine whether the function is a one-to-one function. - f={(17,11),(16,11),(18,17)}\mathrm { f } = \{ ( 17 , - 11 ) , ( - 16 , - 11 ) , ( 18,17 ) \}

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Solve the equation. - log(5+x)log(x3)=log3\log ( 5 + x ) - \log ( x - 3 ) = \log 3

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Solve the equation for x. Give an approximate solution accurate to four decimal places. - ln2x=0.2\ln 2 x = 0.2

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Find the inverse of the one-to-one function. - f(x)=x3+8f ( x ) = x ^ { 3 } + 8

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Use the properties of logarithms to write the expression as a single logarithm. - log6x+4log6xlog6(x+9)\log _ { 6 } x + 4 \log _ { 6 } x - \log _ { 6 } ( x + 9 )

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Write as a logarithmic equation. - 32=93 ^ { 2 } = 9

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