Exam 12: Exponential Functions and Logarithmic Functions

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Solve the problem. -The half-life of Antimony 111 is 2.92.9 hours. If the formula P(t)=(12)t/2.9\mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 } gives the percent (as a decimal) remaining after time tt (in hours), sketch P versus tt .  Solve the problem. -The half-life of Antimony 111 is  2.9  hours. If the formula  \mathrm { P } ( \mathrm { t } ) = \left( \frac { 1 } { 2 } \right) ^ { t / 2.9 }  gives the percent (as a decimal) remaining after time  t  (in hours), sketch P versus  t .

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Find the inverse of the relation. -{(6, -6), (6, -5), (4, -4), (2, -3)}

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Solve the problem. -An accountant tabulated a firm's profits for four recent years in the following table:  Solve the problem. -An accountant tabulated a firm's profits for four recent years in the following table:    The accountant then fit both a linear graph and an exponential curve (seen below) to the data, in order to estimate future profits. Use the linear graph to estimate the profits in the year  2001 .     The accountant then fit both a linear graph and an exponential curve (seen below) to the data, in order to estimate future profits. Use the linear graph to estimate the profits in the year 2001.2001 .  Solve the problem. -An accountant tabulated a firm's profits for four recent years in the following table:    The accountant then fit both a linear graph and an exponential curve (seen below) to the data, in order to estimate future profits. Use the linear graph to estimate the profits in the year  2001 .

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Determine whether the function is one-to-one. - f(x)=7x2+3f ( x ) = 7 x ^ { 2 } + 3

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Determine whether the function is one-to-one. - f(x)=4x2+xf ( x ) = 4 x ^ { 2 } + x

(True/False)
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Graph the equation of the relation using a solid line, and then graph the inverse of the relation using a dashed line. - y=2x2+4xy = 2 x ^ { 2 } + 4 x  Graph the equation of the relation using a solid line, and then graph the inverse of the relation using a dashed line. - y = 2 x ^ { 2 } + 4 x

(Multiple Choice)
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Determine whether the function is one-to-one. - f(x)=(17)xf ( x ) = \left( \frac { 1 } { 7 } \right) ^ { x }

(True/False)
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Graph the equation of the relation using a solid line, and then graph the inverse of the relation using a dashed line. - y=4x3+7y = 4 x ^ { 3 } + 7  Graph the equation of the relation using a solid line, and then graph the inverse of the relation using a dashed line. - y = 4 x ^ { 3 } + 7

(Multiple Choice)
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Determine whether the function is one-to-one. - f(x)=x37f ( x ) = x ^ { 3 } - 7

(True/False)
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Graph. - f(x)=43x2f(x)=4^{3 x-2}  Graph. - f(x)=4^{3 x-2}

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Find f(x) and g(x) such that h(x) = (fg)(x)(f \circ g)(x) . - h(x)=85x+4h ( x ) = \frac { 8 } { \sqrt { 5 x + 4 } }

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Determine whether the function is one-to-one. - f(x)=16x2f ( x ) = 16 - x ^ { 2 }

(True/False)
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Graph. - x=6yx = 6 y  Graph. - x = 6 y

(Multiple Choice)
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Find f(x) and g(x) such that h(x) = (fg)(x)(f \circ g)(x) . - h(x)=(x7)2h ( x ) = ( \sqrt { x } - 7 ) ^ { 2 }

(Multiple Choice)
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Solve the problem. -The half-life of a certain radioactive substance is 22 years. Suppose that at time t=0t = 0 , there are 24 g24 \mathrm {~g} of the substance. Then after t years, the number of grams of the substance remaining will be: N(t)=24(12)t/44N ( t ) = 24 \left( \frac { 1 } { 2 } \right) ^ { t / 44 } How many grams of the substance will remain after 242 years? Round to the nearest hundredth when necessary.

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Solve the problem. -Suppose that $90,000 is invested at 4% interest, compounded annually. Find a function A for the amount in the account after t years.

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Solve the problem. -A size 10 dress in Country C is size 44 in Country D. A function that converts dress sizes in Country C to those in Country DD is f(x)=2(x+12)f ( x ) = 2 ( x + 12 ) . Find a formula for the inverse of the function described.

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Find the inverse of the relation. -{(-6, 2), (-2, 6), (9, -2), (-9, 2)}

(Multiple Choice)
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Use composition to verify whether or not the inverse is correct. - f(x)=3x+6,f1(x)=13x3f ( x ) = 3 x + 6 , f ^ { - 1 } ( x ) = \frac { 1 } { 3 } x - 3

(True/False)
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Find an equation of the inverse of the relation. -y = 6x + 5

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