Exam 6: The Normal Distribution

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The length of country and western songs is normally distributed and has a mean of seconds and a standard deviation of 30 seconds. Find the probability that a random Selection of 16 songs will have mean length of 181.98 seconds or less. Assume the Distribution of the lengths of the songs is normal.

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A normal population has a mean μ=40\mu = 40 and standard deviation σ=11\sigma = 11 . What proportion of the population is between 24 and 32?32 ?

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If a normally distributed group of test scores have a mean of 70 and a standard deviation of 12, find the percentage of scores that will fall below 50.

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The mean weight of loads of rock is 51.0 tons with a standard deviation of 10.0 tons. If 36 loads are chosen at random for a weight check, find the probability that the mean Weight of those loads is less than 50.3 tons. Assume that the variable is normally Distributed.

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For a normal distribution curve with a mean of 15 and a standard deviation of 5, which range of the variable defines an area under the curve corresponding to a probability of Approximately 68%?

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A sample of size 50 will be drawn from a population with mean 76 and standard deviation 14 . Find the 69 th percentile of xˉ\bar { x } .

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The average length of crocodiles in a swamp is 11.5 feet. If the lengths are normally distributed with a standard deviation of 1.7 feet, find the probability that a crocodile is More than 11 feet long.

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The weights of 6-week-old poults (juvenile turkeys) are normally distributed with a mean 8.9 pounds and standard deviation 1.9 pounds. A turkey farmer wants to provide a Money-back guarantee that her 6-week poults will weigh at least a certain amount. What Weight should she guarantee so that she will have to give her customer's money back Only 1% of the time?

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As the sample size nn increases, the shape of the distribution of the sample means taken with replacement from a population with mean μ\mu and standard deviation σ\sigma , will approach a normal distribution. This distribution will have a mean of μ\mu and a standard deviation of σn\frac { \sigma } { \sqrt { n } } . This is a statement of the___________

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Use the normal approximation to find the indicated probability. The sample size is population proportion of successes is pp , and XX is the number of successes in the sample. n=90,p=0.41:P(32<X<43)n = 90 , p = 0.41 : P ( 32 < X < 43 )

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A normal population has a mean μ=28\mu = 28 and standard deviation σ=5\sigma = 5 . What proportion of the population is less than 23 ?

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A recent study found that the life expectancy of a people living in Africa is normally distributed with an average of 53 years with a standard deviation of 7.5 years. If a person In Africa is selected at random, what is the probability that the person will die before the Age of 65?

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A bottler of drinking water fills plastic bottles with a mean volume of 999 milliliters (mL) and standard deviation 5 mL. The fill volumes are normally distributed. What Proportion of bottles have volumes between 992 mL and 998 mL?

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XX is a normally distributed random variable with a mean of 7.07.0 and a standard deviation of 3.00. Find the value xx such that P(X<x)P ( X < x ) is equal to 0.860.86 . (Note: the diagram is not necessarily to scale.) X  is a normally distributed random variable with a mean of  7.0  and a standard deviation of 3.00. Find the value  x  such that  P ( X < x )  is equal to  0.86 . (Note: the diagram is not necessarily to scale.)

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XX is a normally distributed random variable with a mean of 11.0011.00 . If the probability that XX is less than 11.8811.88 is 0.670.67 (as shown below), then what is the standard deviation of (Note: the diagram is not necessarily to scale.) X  is a normally distributed random variable with a mean of  11.00 . If the probability that  X  is less than  11.88  is  0.67  (as shown below), then what is the standard deviation of (Note: the diagram is not necessarily to scale.)

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Which choice is another term that can be used to describe a normal distribution:

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Find the area under the standard normal distribution curve between z=2.05z = - 2.05 and z=z = 2.052.05 .  Find the area under the standard normal distribution curve between  z = - 2.05  and  z =   2.05 .

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The data shown represent quiz scores from Ms. Mayer's 5th grade class. Use the Pearson coefficient to check for skewness. 21 25 9 21 23 22 22 15 23 22 16 11 20 20 17 22 21

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 Find the probability P(0.72<z<0.11) using the standard normal distribution. \text { Find the probability } P ( - 0.72 < z < - 0.11 ) \text { using the standard normal distribution. }

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XX is a normally distributed random variable with a standard deviation of 2.002.00 . Find the mean of XX if 12.71%12.71 \% of the area under the distribution curve lies to the right of 10.2810.28 . (Note: the diagram is not necessarily to scale.) X  is a normally distributed random variable with a standard deviation of  2.00 . Find the mean of  X  if  12.71 \%  of the area under the distribution curve lies to the right of  10.28 . (Note: the diagram is not necessarily to scale.)

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