Exam 3: Functions

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Use the graph to determine the function's domain and range. Write the domain and range in interval notation. -Use the graph to determine the function's domain and range. Write the domain and range in interval notation. -

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The function f is one-to-one. Find its inverse. - f(x)=9x4f ( x ) = \frac { 9 } { x - 4 }

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Graph the function. - f(x)={x+1 if x<13 if x1f ( x ) = \left\{ \begin{array} { l l } x + 1 & \text { if } x < 1 \\- 3 & \text { if } x \geq 1\end{array} \right.  Graph the function. - f ( x ) = \left\{ \begin{array} { l l }  x + 1 & \text { if } x < 1 \\ - 3 & \text { if } x \geq 1 \end{array} \right.

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The graph of a function f is given. Use the graph to answer the question. -Is f(3)positive or negative? The graph of a function f is given. Use the graph to answer the question. -Is f(3)positive or negative?

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Graph the function. - f(x)={x+3 if x<22x3 if x2f(x)=\left\{\begin{array}{ll}-x+3 & \text { if } x<2 \\2 x-3 & \text { if } x \geq 2\end{array}\right.  Graph the function. - f(x)=\left\{\begin{array}{ll} -x+3 & \text { if } x<2 \\ 2 x-3 & \text { if } x \geq 2 \end{array}\right.

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Decide whether or not the functions are inverses of each other. - f(x)=x34,g(x)=x+43f ( x ) = x ^ { 3 } - 4 , g ( x ) = \sqrt [ 3 ] { x + 4 }

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Use the vertical line test to determine whether the graph represents a function. -Use the vertical line test to determine whether the graph represents a function. -

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The function f is one-to-one. Find its inverse. -f(x)= 4x

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Determine whether the relation represents a function. If it is a function, state the domain and range. -Determine whether the relation represents a function. If it is a function, state the domain and range. -

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Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and/or reflecting. - f(x)=15xf ( x ) = \frac { 1 } { 5 x }  Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and/or reflecting. - f ( x ) = \frac { 1 } { 5 x }

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Graph the function. - f(x)=xf(x)=\sqrt{x}  Graph the function. - f(x)=\sqrt{x}

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Find the intersection of the given intervals. - (10,0)[2,10]( - 10,0 ) \cup [ - 2,10 ]

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Based on the graph, determine the range of f. - f(x)={4 if 4x<2x if 2x<8x3 if 8x12f ( x ) = \left\{ \begin{array} { l l } 4 & \text { if } - 4 \leq x < - 2 \\| x | & \text { if } - 2 \leq x < 8 \\\sqrt [ 3 ] { x } & \text { if } 8 \leq x \leq 12\end{array} \right.  Based on the graph, determine the range of f. - f ( x ) = \left\{ \begin{array} { l l }  4 & \text { if } - 4 \leq x < - 2 \\ | x | & \text { if } - 2 \leq x < 8 \\ \sqrt [ 3 ] { x } & \text { if } 8 \leq x \leq 12 \end{array} \right.

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Use the vertical line test to determine whether the graph represents a function. -Use the vertical line test to determine whether the graph represents a function. -

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Graph the function as a solid line or curve and its inverse as a dashed line or curve on the same axes. -f(x)= 5x Graph the function as a solid line or curve and its inverse as a dashed line or curve on the same axes. -f(x)= 5x

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The graph of a function is given. Determine whether the function is increasing, decreasing, or constant on the given interval. -(-3, 0) The graph of a function is given. Determine whether the function is increasing, decreasing, or constant on the given interval. -(-3, 0)

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Find the x-intercept(s)and the y-intercept of the function. - f(x)=x3+8x2x8f ( x ) = x ^ { 3 } + 8 x ^ { 2 } - x - 8

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Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and/or reflecting. - f(x)=xf(x)=|-x|  Graph the function by starting with the graph of the basic function and then using the techniques of shifting, compressing, stretching, and/or reflecting. - f(x)=|-x|

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The function f is one-to-one. Find its inverse. - f(x)=6x+4f ( x ) = 6 x + 4

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Decide whether or not the functions are inverses of each other. - f(x)=7x7,g(x)=17x+1f ( x ) = 7 x - 7 , g ( x ) = \frac { 1 } { 7 } x + 1

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