Exam 4: Series Circuits

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In a series circuit, total power PT is calculated as:

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What type of resistor could be used as variable voltage-divider?

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Four series resistors are connected across a 30 V source and carry 0.125mA . If R1=10 kO\mathrm { kO } , R2=33 kΩ\mathrm { k } \Omega and R3=47 kΩ\mathrm { k } \Omega , what is the value of R4 ?

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    \text { Figure } 4 < 1  -What is the total resistance in Figure  4-1  if  R<sub>1</sub>=10   \mathrm { k } \Omega , R<sub>2</sub>=10   \mathrm { k } \Omega  and  R<sub>3</sub>=15   k \Omega  ?  Figure 4<1\text { Figure } 4 < 1 -What is the total resistance in Figure 4-1 if R1=10 kΩ\mathrm { k } \Omega , R2=10 kΩ\mathrm { k } \Omega and R3=15 kΩk \Omega ?

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Voltage sources in series increase both voltage and current capacity.

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A series circuit has multiple current paths.

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If a 68 If a  68 , 33 , 100   and  47 \Omega    resistor are connected in series across a  9 V battery, the current equals , 33 If a  68 , 33 , 100   and  47 \Omega    resistor are connected in series across a  9 V battery, the current equals , 100 If a  68 , 33 , 100   and  47 \Omega    resistor are connected in series across a  9 V battery, the current equals and 47 Ω\Omega resistor are connected in series across a 9 V battery, the current equals

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If a 100 If a  100 , 220 \Omega  . and  330  resistor are connected in series, total resistance equals , 220 Ω\Omega . and 330 If a  100 , 220 \Omega  . and  330  resistor are connected in series, total resistance equals resistor are connected in series, total resistance equals

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Kirchhoffʹs Voltage Law states that the algebraic sum of all the voltages around a closed path is zero.

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If 5 V and 16 V power supplies are connected in series aiding,W hat is the total voltage?

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If 12 V and 17 V sources are Wired in series aiding,What is the total supply voltage?

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If -12 V and -6 V are connected so they equal -18 V, these sources are ________.

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In a series circuit, the current is the same at every point in the circuit.

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If a resistor is dissipating 1/4 W, it can supply 1/4 W to the load.

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(a) (a)  Figure  4 < 2   -Refer to Figure 4-2a. Voltage from C to ground is 100 V. What is the probable cause of failure? Figure 4<24 < 2 -Refer to Figure 4-2a. Voltage from C to ground is 100 V. What is the probable cause of failure?

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According to Kirchhoffʹs Voltage Law, the sum of the individual voltage drops in a series circuit equals the source Voltage.

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    \text { Figure } 4 < 1  - R<sub>1</sub>=4.7  \mathrm { k } \Omega  , R<sub>2</sub>=4.7  \mathrm { k } \Omega  and R<sub>3</sub>=4.7  \mathrm { k } \Omega   in Figure  4-1 .  What is  RT if  R<sub>2</sub> shorts?  Figure 4<1\text { Figure } 4 < 1 - R1=4.7 kΩ\mathrm { k } \Omega , R2=4.7 kΩ\mathrm { k } \Omega and R3=4.7 kΩ\mathrm { k } \Omega in Figure 4-1 . What is RT if R2 shorts?

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One of the most popular applications of a potentiometer is as an adjustable voltage divider also known as a:

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    \text { Figure } 4 < 1  -Calculate the current in Figure  4-1  if  \mathrm { VR } 1   =16 V, R<sub>1</sub>=10  \mathrm { k } \Omega , R<sub>2</sub>=10 \mathrm { kQ }  and  R<sub>3</sub>=15  k \Omega  .  Figure 4<1\text { Figure } 4 < 1 -Calculate the current in Figure 4-1 if VR1\mathrm { VR } 1 =16 V, R1=10 kΩ\mathrm { k } \Omega , R2=10 kQ\mathrm { kQ } and R3=15 kΩk \Omega .

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A 50 kΩ\mathrm { k } \Omega potentiometer is connected across a 15 V source. If the voltage from the wiper to the lower end of the potentiometer is 3.2 V , what is the resistance of that lower part?

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