Exam 8: Magnetic Forces
Exam 1: Electric Fields46 Questions
Exam 2: Gausss Law44 Questions
Exam 3: Electric Potential49 Questions
Exam 4: Energy and Capacitance38 Questions
Exam 5: Current and Resistance33 Questions
Exam 6: Direct-Current Circuits49 Questions
Exam 7: Magnetic Fields45 Questions
Exam 8: Magnetic Forces50 Questions
Exam 9: Faradays Law49 Questions
Exam 10: Inductance23 Questions
Exam 11: Alternating-Current Circuits50 Questions
Exam 12: Electromagnetic Waves40 Questions
Exam 13: The Nature of Light and the Principles of Ray Optics38 Questions
Exam 14: Image Formation45 Questions
Exam 15: Wave Optics43 Questions
Exam 16: Diffraction Patterns and Polarisation44 Questions
Exam 17: Quantisation and Wave-Particle Duality41 Questions
Exam 18: Introduction to Quantum Mechanics43 Questions
Exam 19: Atomic Physics49 Questions
Exam 20: Quantum Physics of Molecules and Solids46 Questions
Exam 21: Nuclei and Radioactivity48 Questions
Exam 22: Particle Physics34 Questions
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A particle (q =-4.0 C, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that is 50 away from that of the magnetic field.The particle is observed to have an acceleration with a magnitude of 5.8 m/s2.What is the magnitude of the magnetic field?
(Multiple Choice)
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A circular loop (radius = 0.50 m) carries a current of 3.0 A and has unit normal vector of ()/3.What is the x component of the torque on this loop when it is placed in a uniform magnetic field of ()T?



(Multiple Choice)
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A current of 4.0 A is maintained in a single circular loop having a circumference of 80 cm.An external magnetic field of 2.0 T is directed so that the angle between the field and the plane of the loop is 20 .Determine the magnitude of the torque exerted on the loop by the magnetic forces acting upon it.
(Multiple Choice)
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An electron moving in the positive x direction experiences a magnetic force in the positive z direction.If Bx = 0, what is the direction of the magnetic field?
(Multiple Choice)
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What is the kinetic energy of an electron that passes undeviated through perpendicular electric and magnetic fields if E = 4.0 kV/m and B = 8.0 mT?
(Multiple Choice)
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A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T.What is the radius of the resulting circular path? (deuteron: m = 3.3 *10-27 kg, q = 1.6*10-19 C)
(Multiple Choice)
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The reason the north pole of a bar magnet free to rotate points north is because:
(Multiple Choice)
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A circular coil (radius = 0.40 m) has 160 turns and is in a uniform magnetic field.When the orientation of the coil is varied through all possible positions, the maximum torque on the coil by magnetic forces is 0.16 N . m when the current in the coil is 4.0 mA.What is the magnitude of the magnetic field?
(Multiple Choice)
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A 2.0-C charge moves with a velocity of () m/s and experiences a magnetic force of () N.The x component of the magnetic field is equal to zero.Determine the y component of the magnetic field.



(Multiple Choice)
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A particle (mass = 6.0 mg) moves with a speed of 4.0 km/s in a direction that makes an angle of 37 above the positive x axis in the xy plane.At the instant it enters a magnetic field of (5.0) mT it experiences an acceleration of (8.0) m/s2.What is the charge of the particle?


(Multiple Choice)
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The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped turns each carrying a current I.The magnetic field in the region is () mT.The loop can turn about the y axis.If = 30 , a = 0.40 m, b = 0.30 m, and I = 8.0 A, what is the magnitude of the torque exerted on the loop?


(Multiple Choice)
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A charged particle (mass = M, charge = Q > 0) moves in a region of space where the magnetic field has a constant magnitude of B and a downward direction.What is the magnetic force on the particle at an instant when it is moving horizontally toward the north with a speed V?
(Multiple Choice)
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A charged particle (mass = 4.0 g, charge = 5.0 C) moves in a region where the only force on it is magnetic.What is the magnitude of the acceleration of the particle at a point where the speed of the particle is 5.0 km/s, the magnitude of the magnetic field is 8.0 mT, and the angle between the direction of the magnetic field and the velocity of the particle is 60 ?
(Multiple Choice)
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The point P lies along the perpendicular bisector of the line connecting two long straight wires S and T that are perpendicular to the page.A set of directions A through H is shown next to the diagram.When the two equal currents in the wires are directed up out of the page, the direction of the magnetic field at P is closest to the direction of: 

(Multiple Choice)
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An electron moves in a region where the magnetic field is uniform, has a magnitude of 60 T, and points in the positive x direction.At t = 0 the electron has a velocity that has an x component of 30 km/s, a y component of 40 km/s, and a z component of zero.What is the radius of the resulting helical path?
(Multiple Choice)
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Bert says that a charged particle in a vacuum can travel in a helix only if a uniform electric field and a uniform magnetic field are both present and both parallel to the axis of the helix.Stuart says that only a magnetic field with a component parallel to the axis of the helix is needed.Which one, if either, is correct, and why?
(Multiple Choice)
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A physicist claims that she has found a new particle with a mass 200 000 times the mass of the proton (1.67*10-27 kg) and a charge of 3.20 *10-19 C.If she is correct, such a particle travelling in a circle in a uniform 5.00 T magnetic field at a velocity of 2500 m/s will have a radius of:
(Multiple Choice)
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One reason why we know that magnetic fields are not the same as electric fields is because the force exerted on a charge +q:
(Multiple Choice)
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You stand near the Earth's equator.A positively charged particle that starts moving parallel to the surface of the Earth in a straight line directed east is initially deflected upwards.If you know there are no electric fields in the vicinity, a possible reason why the particle does not initially acquire a downward component of velocity is because near the equator the magnetic field lines of the Earth are directed:
(Multiple Choice)
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The boundary shown is that of a uniform magnetic field directed in the positive z direction.An electron enters the magnetic field with a velocity pointing along the x axis and exits 0.63 s later at point A.What is the magnitude of the magnetic field?

(Multiple Choice)
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