Exam 11: Conic Sections

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Graph the inequality. - (x+1)2+(y4)24( x + 1 ) ^ { 2 } + ( y - 4 ) ^ { 2 } \geq 4  Graph the inequality. - ( x + 1 ) ^ { 2 } + ( y - 4 ) ^ { 2 } \geq 4

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Solve the problem. -The perimeter of a rectangle is 34 inches and its area is 42 square inches. What are its dimensions?

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Solve the problem. -Simple interest is calculated using the formula, interest = principal · rate · time or i = prt. Jenny Brooks invested a certain amount of money saved for 1 year at a certain annual interest rate (simple interest)yielded $16.83 in Interest. If we had added $34 to the principal and reduced the interest rate by 2 percentage point(s), the interest Would have been the same. Find the principal and the rate.

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Write the equation in the form y=a(xh)2+k or x=a(yk)2+h\mathbf {y = a ( x - h ) ^ { 2 } + k ~or ~ x = a ( y - k ) ^ { 2 } + h} h a nd then graph the equation. - y=x2+4x5y = x ^ { 2 } + 4 x - 5  Write the equation in the form  \mathbf {y = a ( x - h ) ^ { 2 } + k ~or ~ x = a ( y - k ) ^ { 2 } + h}  h a nd then graph the equation. - y = x ^ { 2 } + 4 x - 5

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Indicate whether the equation represents an ellipse, hyperbola, circle, or parabola. In equations that contain bothth x2x ^ { 2 } 2 and y2y ^ { 2 } terms, divide both terms, divide bothsides of the equation by the constant term to put the equation in a more recognizable form. - 8x2+17y2=208 x ^ { 2 } + 17 y ^ { 2 } = 20

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Graph the equation. - 49x2+y2=4949 x ^ { 2 } + y ^ { 2 } = 49  Graph the equation. - 49 x ^ { 2 } + y ^ { 2 } = 49

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Find the equation of the ellipse satisfying the given conditions. -(0, 6), (0, -6), (3, 0), (-3, 0)are the endpoints of the major and minor axes.

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Write the equation of the circle with the given center and radius. -  Center (0,8), radius 17\text { Center } ( 0 , - 8 ) , \quad \text { radius } \sqrt { 17 }

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Determine the solution to the system of inequalities. - y\geq-10x+25 +>36  Determine the solution to the system of inequalities. - \begin{array} { l }  y \geq x ^ { 2 } - 10 x + 25 \\ x ^ { 2 } + y ^ { 2 } > 36 \end{array}

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Solve the problem. -The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 34 feet and the height of the arch over the center of the roadway is 12 feet. Two trucks plan to use This road. They are both 8 feet wide. Truck 1 has an overall height of 12 feet and Truck 2 has an overall height of 11 feet. Draw a rough sketch of the situation and determine which of the trucks can pass under the bridge.

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Graph the equation. - x=12(y4)2+1x = \frac { 1 } { 2 } ( y - 4 ) ^ { 2 } + 1  Graph the equation. - x = \frac { 1 } { 2 } ( y - 4 ) ^ { 2 } + 1

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Graph the equation. - (x3)2+y2=4( x - 3 ) ^ { 2 } + y ^ { 2 } = 4  Graph the equation. - ( x - 3 ) ^ { 2 } + y ^ { 2 } = 4

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Graph the inequality. - x225y291\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } \geq 1  Graph the inequality. - \frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 9 } \geq 1

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Write the following equation in standard form. Determine the center of the ellipse. - 16x2+64x+9y254y+1=016 x ^ { 2 } + 64 x + 9 y ^ { 2 } - 54 y + 1 = 0

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Solve the problem. -For the given cost and revenue equations, find the break-even point(s)C C=80x,R=0.2x290xC = 80 x , R = 0.2 x ^ { 2 } - 90 x

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Write the equation of the circle. Assume the radius is a whole number. -Write the equation of the circle. Assume the radius is a whole number. -

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Graph the equation. - x24+y29=1\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 9 } = 1  Graph the equation. - \frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 9 } = 1

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Write the equation in the form y=a(xh)2+k or x=a(yk)2+h\mathbf {y = a ( x - h ) ^ { 2 } + k ~or ~ x = a ( y - k ) ^ { 2 } + h} h a nd then graph the equation. - y=3x2+18x31y = - 3 x ^ { 2 } + 18 x - 31  Write the equation in the form  \mathbf {y = a ( x - h ) ^ { 2 } + k ~or ~ x = a ( y - k ) ^ { 2 } + h}  h a nd then graph the equation. - y = - 3 x ^ { 2 } + 18 x - 31

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Find all real solutions to the system of equations using the addition method. - +=80 -=-48

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Determine the equations of the asymptotes for the equation. - x225y216=1\frac { x ^ { 2 } } { 25 } - \frac { y ^ { 2 } } { 16 } = 1

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