Question 1

Write the equation of the circle with the given center and radius.
-Center (0, 0),radius 3

Accepted Answer

A)  $x ^ { 2 } - y ^ { 2 } = 3$ 
B)  $x ^ { 2 } + y ^ { 2 } = 6$ 
C)  $x ^ { 2 } + y ^ { 2 } = 9$ 
D)  $x ^ { 2 } + y ^ { 2 } = 3$ 
A)  $x ^ { 2 } - y ^ { 2 } = 3$ 
B)  $x ^ { 2 } + y ^ { 2 } = 6$ 
C)  $x ^ { 2 } + y ^ { 2 } = 9$ 
D)  $x ^ { 2 } + y ^ { 2 } = 3$

Question 2

Solve the problem.
-A rectangular piece of tin has an area of 496 square inches. A square of 2 inches is cut from each corner, and an open box is made by turning up the ends and sides. If the volume of the box is 648 cubic inches, what were the
Original dimensions of the piece of tin?

Accepted Answer

A) 18 in. by 33 in. 
B) 12 in. by 25 in. 
C) 16 in. by 31 in. 
D) 14 in. by 29 in. 
A) 18 in. by 33 in. 
B) 12 in. by 25 in. 
C) 16 in. by 31 in. 
D) 14 in. by 29 in.

Question 3

Graph the equation.
-$\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1$

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)

Question 4

Graph the equation.
-$x = - ( y + 3 ) ^ { 2 } + 3$

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)

Question 5

Write the equation of the circle. Assume the radius is a whole number.
-

Accepted Answer

A)  $( x - 1 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 1$ 
B)  $( x - 4 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 1$ 
C)  $( x + 1 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 1$ 
D)  $( x + 4 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 1$ 
A)  $( x - 1 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 1$ 
B)  $( x - 4 ) ^ { 2 } + ( y - 1 ) ^ { 2 } = 1$ 
C)  $( x + 1 ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 1$ 
D)  $( x + 4 ) ^ { 2 } + ( y + 1 ) ^ { 2 } = 1$

Question 6

Graph the inequality.
-$y < - x ^ { 2 } + 6 x - 9$

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)

Question 7

Graph the equation.
-$\frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)

Question 8

Write the equation in standard form (if necessary)and determine the equations of the asymptotes. Then graph the
equation.
-$\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 9 } = 1$

Accepted Answer

A)  $y = \pm \frac { 2 } { 3 } x$
  
B)  $y = \pm \frac { 3 } { 2 } x$
  
C)  $y = \pm \frac { 3 } { 2 } x$
  
D)  $y = \pm \frac { 2 } { 3 } x$
  
A)  $y = \pm \frac { 2 } { 3 } x$
  
B)  $y = \pm \frac { 3 } { 2 } x$
  
C)  $y = \pm \frac { 3 } { 2 } x$
  
D)  $y = \pm \frac { 2 } { 3 } x$

Question 9

Graph the equation.
-$y = ( x - 6 ) ^ { 2 } - 5$

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)

Question 10

Write the equation of the circle with the given center and radius.
-Center (0, -10), radius 5

Accepted Answer

A)  $x ^ { 2 } + ( y + 10 ) ^ { 2 } = 25$ 
B)  $( x + 10 ) ^ { 2 } + y ^ { 2 } = 25$ 
C)  $x ^ { 2 } + ( y - 10 ) ^ { 2 } = 5$ 
D)  $( x - 10 ) ^ { 2 } + y ^ { 2 } = 25$ 
A)  $x ^ { 2 } + ( y + 10 ) ^ { 2 } = 25$ 
B)  $( x + 10 ) ^ { 2 } + y ^ { 2 } = 25$ 
C)  $x ^ { 2 } + ( y - 10 ) ^ { 2 } = 5$ 
D)  $( x - 10 ) ^ { 2 } + y ^ { 2 } = 25$

Question 11

Determine the midpoint of the line segment between the pair of points.
-(3, -7)and (8, -3)

Accepted Answer

A) (11, -10) 
B) (-5, -4) 
C)  $\left( \frac { 11 } { 2 } , - 5 \right)$ 
D)  $\left( - \frac { 5 } { 2 } , - 2 \right)$ 
A) (11, -10) 
B) (-5, -4) 
C)  $\left( \frac { 11 } { 2 } , - 5 \right)$ 
D)  $\left( - \frac { 5 } { 2 } , - 2 \right)$

Question 12

Name the conic.
-

Accepted Answer

A) circle 
B) hyperbola 
C) parabola 
D) ellipse 
A) circle 
B) hyperbola 
C) parabola 
D) ellipse

Write the equation of the circle with the given center and radius. -Center (0, 0),radius 3

Solve the problem. -A rectangular piece of tin has an area of 496 square inches. A square of 2 inches is cut from each corner, and an open box is made by turning up the ends and sides. If the volume of the box is 648 cubic inches, what were the Original dimensions of the piece of tin?

Graph the equation. - $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1$ $Graph the equation. - \frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1$

Graph the equation. - $x = - ( y + 3 ) ^ { 2 } + 3$ $Graph the equation. - x = - ( y + 3 ) ^ { 2 } + 3$

Write the equation of the circle. Assume the radius is a whole number. -

Graph the inequality. - $y < - x ^ { 2 } + 6 x - 9$ $Graph the inequality. - y < - x ^ { 2 } + 6 x - 9$

Graph the equation. - $\frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$ $Graph the equation. - \frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$

Graph the equation. - $y = ( x - 6 ) ^ { 2 } - 5$ $Graph the equation. - y = ( x - 6 ) ^ { 2 } - 5$

Write the equation of the circle with the given center and radius. -Center (0, -10), radius 5

Determine the midpoint of the line segment between the pair of points. -(3, -7)and (8, -3)

Name the conic. -

Basic Concepts

Equations and Inequalities

Graphs and Functions

Systems of Equations and Inequalities

Polynomials and Polynomial Functions

Rational Expressions and Equations

Roots, Radicals, and Complex Numbers

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Characteristics of Functions and Their Graphs

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Exam 11: Conic Sections

Write the equation of the circle with the given center and radius. -Center (0, 0),radius 3

Solve the problem. -A rectangular piece of tin has an area of 496 square inches. A square of 2 inches is cut from each corner, and an open box is made by turning up the ends and sides. If the volume of the box is 648 cubic inches, what were the Original dimensions of the piece of tin?

Graph the equation. - (x−1)24+(y+2)216=1\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 14(x−1)2​+16(y+2)2​=1

Graph the equation. - x=−(y+3)2+3x = - ( y + 3 ) ^ { 2 } + 3x=−(y+3)2+3

Write the equation of the circle. Assume the radius is a whole number. -

Graph the inequality. - y<−x2+6x−9y < - x ^ { 2 } + 6 x - 9y<−x2+6x−9

Graph the equation. - (x−2)29+(y+2)24=1\frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 19(x−2)2​+4(y+2)2​=1

Write the equation in standard form (if necessary)and determine the equations of the asymptotes. Then graph the equation. - x24−y29=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 9 } = 14x2​−9y2​=1

Graph the equation. - y=(x−6)2−5y = ( x - 6 ) ^ { 2 } - 5y=(x−6)2−5

Write the equation of the circle with the given center and radius. -Center (0, -10), radius 5

Determine the midpoint of the line segment between the pair of points. -(3, -7)and (8, -3)

Name the conic. -

Basic Concepts

Equations and Inequalities

Graphs and Functions

Systems of Equations and Inequalities

Polynomials and Polynomial Functions

Rational Expressions and Equations

Roots, Radicals, and Complex Numbers

Quadratic Functions

Exponential and Logarithmic Functions

Characteristics of Functions and Their Graphs

Sequences, Series, and Probability

Filters

Graph the equation. - $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1$ $Graph the equation. - \frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 2 ) ^ { 2 } } { 16 } = 1$

Graph the equation. - $x = - ( y + 3 ) ^ { 2 } + 3$ $Graph the equation. - x = - ( y + 3 ) ^ { 2 } + 3$

Graph the inequality. - $y < - x ^ { 2 } + 6 x - 9$ $Graph the inequality. - y < - x ^ { 2 } + 6 x - 9$

Graph the equation. - $\frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$ $Graph the equation. - \frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { ( y + 2 ) ^ { 2 } } { 4 } = 1$

Graph the equation. - $y = ( x - 6 ) ^ { 2 } - 5$ $Graph the equation. - y = ( x - 6 ) ^ { 2 } - 5$