Exam 7: Rational Expressions and Equations

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Solve the problem. -For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is directly proportional to the square of the voltage across the resistor. The resistor must dissipate Solve the problem. -For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is directly proportional to the square of the voltage across the resistor. The resistor must dissipate   watt of Power when the voltage across the resistor is 13 volts. Find the power that the resistor must dissipate when the Voltage across it is 26 volts. watt of Power when the voltage across the resistor is 13 volts. Find the power that the resistor must dissipate when the Voltage across it is 26 volts.

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Solve the equation and check your solution. -Solve the equation and check your solution. -

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Add or subtract. -Add or subtract. -

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Find the quantity indicated. -h varies directly as f and inversely as g. Find k when h = 4, f = 52, and g = 65.

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Simplify. -Simplify. -

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Find the quantity indicated. -f varies jointly as Find the quantity indicated. -f varies jointly as   and h, and f = 36 when q = 2 and h = 3. Find q when f = 288 and h = 6. and h, and f = 36 when q = 2 and h = 3. Find q when f = 288 and h = 6.

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Solve the equation and check your solution. -Solve the equation and check your solution. -

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Divide. -Divide. -

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Simplify. -Simplify. -

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Add or subtract. -Add or subtract. -

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Add or subtract. -Add or subtract. -

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Simplify. -Simplify. -

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Add or subtract. -Add or subtract. -

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Simplify. -Simplify. -

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Solve the problem. -If the force acting on an object stays the same, then the acceleration of the object is inversely proportional to its mass. If an object with a mass of 16 kilograms accelerates at a rate of 10 meters per second per second by a force, Find the rate of acceleration of an object with a mass of 4 kilograms that is pulled by the same force.

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Solve the problem. -The gravitational attraction between two masses varies inversely as the square of the distance between them. If the force of attraction is 9 lb when the masses are 2 ft apart, what is the attraction when the masses are 6 ft Apart?

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Add or subtract. -Add or subtract. -

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Solve the problem and answer the question. -A car travels 400 miles on level terrain in the same amount of time it travels 160 miles on mountainous terrain. If the rate of the car is 30 miles per hour less in the mountains than on level ground, find its rate in the Mountains.

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Solve the equation and check your solution. -Solve the equation and check your solution. -

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Answer true or false. -Answer true or false. -

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