Exam 7: Factoring, Solving Equations and Problem Solving

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Factor the following polynomial completely. 2a4322 a ^ { 4 } - 32

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Find two consecutive positive odd whole numbers whose product is 143.

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Solve the equation. 16y(y+1)=316 y ( y + 1 ) = - 3

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Solve the equation. 4t212t=04 t ^ { 2 } - 12 t = 0

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Find the greatest common factor of the given expression. 15z4c6,10z3c7 and 55z6c215 z ^ { 4 } c ^ { 6 } , 10 z ^ { 3 } c ^ { 7 } \text { and } 55 z ^ { 6 } c ^ { 2 }

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Solve the equation. 7y(7y+3)=47 y ( 7 y + 3 ) = 4

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Solve the equation. x2+6x=7x ^ { 2 } + 6 x = 7

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Find three negative consecutive integers such that the product of the two smaller integers is 116 more than ten times the largest integer.

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Set up an equation and solve the problem. 7 times the square of a number equals 175. Find the number. Please enter your answer as two numbers, separated by a comma.

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Solve the equation. x22x63=0x ^ { 2 } - 2 x - 63 = 0 Please enter your answer as two numbers, separated by a comma.

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Find the greatest common factor of the given expressions. 45xa,20xa5 and 85x2a45 x a , 20 x a ^ { 5 } \text { and } 85 x ^ { 2 } a

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Factor the trinomial completely. Indicate if it is not factorable using integers. 28x2144x+2028 x ^ { 2 } - 144 x + 20

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Solve the equation. 16x218x9=016 x ^ { 2 } - 18 x - 9 = 0 Please enter your answer as two numbers, separated by a comma.

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Set up an equation and solve the problem. 81 less than the square of a number equals zero. Find the number. Please enter your answer as two numbers, separated by a comma.

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Factor the polynomial completely. Don t forget to look for a common monomial factor first. x2+25y2x ^ { 2 } + 25 y ^ { 2 }

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Factor the following trinomial completely. x2+7xy8y2x ^ { 2 } + 7 x y - 8 y ^ { 2 }

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Set up an equation and solve the problem. The difference of the areas of two squares is 6,912 square inches. Each side of the larger square is 7 times the length of a side of the smaller square. Find the length of a side of the larger square. __________ inches

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Solve the equation. 4y2+24y=04 y ^ { 2 } + 24 y = 0

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The length of one leg of a right triangle is 1 centimeter more than the length of the other leg. The length of the hypotenuse is 5 centimeters. Find the lengths of the two legs.

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Solve the equation. 21(z9)z(z9)=021 ( z - 9 ) - z ( z - 9 ) = 0

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