Exam 6: Standard Errors

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In your own words, try to explain the meaning and importance of the central limit theorem.

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This states that as sample sizes increase, the sampling distribution of the mean looks more and more like a normal distribution. With sample sizes of 30 or more the sampling distribution of the mean will be a normal distribution, which allows one to calculate probabilities based on the normal distribution.

Suppose that instead of having a sample of 25 in question #7, I had a sample of 100. Tell me how this would affect the results and why it makes sense that the results would be affected in this way.

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If my sample size were 100, my standard error would be smaller (because larger samples should look more like the population, therefore reducing error). With a smaller standard error in the denominator of the formula for calculating a z score, I would end up with a larger z score. Larger z scores would be associated with smaller probabilities, so the chances of getting a sample mean of 11 when the population mean is 10 would be much smaller than .1056, if the sample was randomly selected and the n = 100. Here's what it would look like:
σxˉ\sigma_{\bar{x}} =
4100\frac{4}{\sqrt{100}}
= 4/10= .4
Now, to calculate my z score I go: z =
1110.4\frac{11-10}{.4}
\rightarrow 1/.4 = 2.5.
Area beyond z is 1 - .9938 = .0062.

Suppose that in the population of American college students the average number of alcoholic drinks consumed per week is 12. What is the probability of randomly selecting a sample (n = 16) with a mean of 10 and a standard deviation of 4? (Hint: Tell me the two probabilities it will be between using a 2-tailed value)

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So I do not know the population standard deviation here, which means I'll have to look in Appendix B using the t values. First, I must calculate a standard error of the mean:
SxˉS_{\bar{x}} = 4/square root of 16 \rightarrow 4/4 \rightarrow 1.
Next I calculate a t value: t = 10 - 12/1 = -2/1 = -2.00.
My degrees of freedom will be 16 = 1 = 15.
So in Appendix B, looking at 15 degrees of freedom I find a value of 1.753 and a value of 2.131. These are the two closest values to 2.00. Then I look up at the top of the table and find that these correspond with alpha levels of .10 and .05. So the best I can do is say that the probability of getting a sample mean of 10 from this population, when the sample is randomly selected and n = 16, is between 5% and 10%.

Please tell me the definition of "standard error" and then tell me, in your own words, what the standard error of the mean tells you.

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Suppose that I am interested in creating a sampling distribution of the mean. The sample sizes are 40 and the population is undergraduate students. Given this information, tell me how you would create a sampling distribution of the mean for the variable of calories consumed per day.

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Take a look at the formulas for calculating the standard error of the mean in Chapter 6. Explain why it makes sense to have the standard deviation in the numerator and the sample size in the denominator. (When I say "makes sense" I mean both mathematically and conceptually. In other words, why does it make sense that as the standard deviation increases the standard error also increases? And why does it make sense that as the sample size increases the standard error decreases?)

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Suppose that in the population of chickens, the average number of feathers per chicken is 1000 with a standard deviation of 200. Suppose that I select a random sample of 64 birds from this population. What is the probability that this sample will have a mean of 950 feathers or fewer?

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When using standard errors to calculate probabilities of events occurring by chance, how do you know when to use z scores and when to use t values?

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Why does it make sense that a larger sample size will produce a smaller standard error of the mean?

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Suppose that I know that in the population of bees in California, the average number of flowers pollinated per day is 10 with a standard deviation of 4. I select a random sample of 25 California bees. What is the probability that my sample mean will be 11 or more flowers pollinated?

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