Exam 13: Factorial Anova: Fixed-Effects Mode

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Complete the following ANOVA summary table for a two-factor fixed-effects ANOVA, where there are two levels of factor A (type of counseling) and four levels of factor B (frequency of counseling). Each cell includes six people and α\alpha = .01. Source SS df MS F Critical Value Decision 60 6 60 Within Total 640

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A has 2 levels, so J = 2. B has 4 levels, so K = 4.

Each cell has 6 people, so n = 6. N = 2*4*6 = 48.

dfA = J - 1 = 2 - 1 = 1, dfB = K - 1 = 4 - 1 = 3, dfAB = (J - 1)(K - 1) = 1*3 = 3, dfwith = N - JK = 48 - 2*4 = 40, dftotal = N - 1 = 48 - 1 = 47.

MSA = SSA/dfA = 60/1 = 60, MSAB = SSAB/dfAB = 60/3 = 20,
MSwith = MSA/FA = 60/6 = 10; SSwith = MSwith*dfwith = 10*40 = 400,
SSB = SStotal - SSA - SSAB - SSwith = 640 - 60 - 60 - 400 = 120;
MSB = MSB/FB = 120/3 = 40
FA = MSA/MSwith = 60/10 = 6; critical value = .01F1,40 = 7.31 > FA, fail to reject H0.

FB = MSB/MSwith = 40/10 = 4; critical value = .01F3,40 = 4.31 > FB, fail to reject H0.
FAB = MSAB/MSwith = 20/10 = 2; critical value = .01F3,40 = 4.31 > FAB, fail to reject H0.

 Source SSdfMSF Critical Value  Decision A601606.01F1,40=7.31 Fail to reject H0 B1203404.01F3,40=4.31 Fail to reject H0AB603202.01F3,40=4.31 Fail to reject H0 Within 4004010\begin{array}{crrrrcc}\text { Source } & S S & d f & M S & F & \text { Critical Value } & \text { Decision } \\\hline \mathrm{A} & 60 & 1 & 60 & 6 & .01 F_{1,40}=7.31 & \text { Fail to reject } H_{0} \\\mathrm{~B} & 120 & 3 & 40 & 4 & .01 F_{3,40}=4.31 & \text { Fail to reject } H_{0} \\\mathrm{AB} & 60 & 3 & 20 & 2 & .01 F_{3,40}=4.31 & \text { Fail to reject } H_{0} \\\text { Within } & 400 & 40 & 10 & & & \\\hline\end{array}

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