Exam 4: Monadic Predicate Logic

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refer to the following formula: ∼(∀x){(Ix • Jx) ⊃ [Kx ≡ (La • Lb)]} -Which of the following variables in the formula are free?

(Multiple Choice)
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1. (∀x)Ix \lor ∼(∃x)Hx 2. (∃x)Jx ⊃ ∼(∀x)Ix 3. Hc / (∀x)∼Jx -Which of the following propositions is an appropriate assumption for an indirect proof of the conclusion of the given argument?

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select the best translation into predicate logic. -Only consistent rationalists are apriorists.

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refer to the following formula: ∼(∀x){(Ix • Jx) ⊃ [Kx ≡ (La • Lb)]} -Which variables are bound by the '(∀x)'?

(Short Answer)
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Translate each of the following sentences into predicate logic, using the given constants and predicates. -Bonita doesn't study law; she's pre-med. (b: Bonita; Lx: x studies law; Mx: x is pre-med)

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provide a conterexample in a finite domain to each given invalid argument. -1. (∀x)(Kx \lor Lx) 2. (∃x)∼Kx / (∀x)Lx

(Essay)
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Translate each of the following sentences into predicate logic, using the given constants and predicates. -If Tranh takes a sabbatical then neither she nor Minh will feel overworked. (m: Minh; t: Tranh; Ox: x feels overworked; Sx: x takes a sabbatical)

(Short Answer)
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provide a conterexample in a finite domain to each given invalid argument. -1. (∃x)(Mx • Nx) 2. (∀x)(Ox ⊃ Mx) / (∀x)(Ox ⊃ Nx)

(Essay)
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Some materialist empiricists are either libertarians or hard determinists. But no empiricist is a hard determinist. So some materialists are libertarians. -Which of the following is the best translation into M of this argument?

(Multiple Choice)
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construct theories for which the following interpretation is a model (i.e. construct at least two sentences which are true under the given interpretation). Domain = {1, 2, 3, ..., 28, 29, 30} E = {2, 4, 6, ..., 28, 30} O = {1, 3, 5, ..., 27, 29} P = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29} a = 1 d = 19 b = 2 e = 23 c = 3 f = 29 -Construct a theory of at least three sentences which uses all three predicates and at least three different constants.

(Essay)
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derive the conclusions of each of the following arguments using the rules of inference for M. Do not use conditional or indirect proof. -1. ∼(∃x)[Fx • (Gx • Hx)] 2. ∼(∃x)(Ix • ∼Fx) / (∀x)[Ix ⊃ (∼Gx \lor ∼Hx)]

(Essay)
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determine whether the given argument is valid or invalid. If it is invalid, select a counterexample. -1. (∃x)(Jx • ∼Kx) ⊃ (∃x)(Lx • Mx) 2) (∃x)(Jx • Lx) 3) ∼(∃x)(Jx • Kx) / ∼(∀x)(Lx ⊃ Mx)

(Multiple Choice)
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1. (∀x)(Fx ⊃ ∼Gx) 2. (∃x)(Hx • Gx) -Which of the following propositions is an immediate (one-step) consequence in M of the given premises?

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Translate each of the following sentences into predicate logic, using the given constants and predicates. -Some blankets are not soft. (Bx: x is a blanket; Sx: x is soft)

(Short Answer)
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select the best translation into predicate logic. -Berkeley is an empiricist and Hume is not an apriorist.

(Multiple Choice)
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Translate each of the following sentences into predicate logic, using the given constants and predicates. -No red flowers are in the garden. (Fx: x is a flower; Gx: x is in the garden; Rx: x is red)

(Short Answer)
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construct a model for each of the given theories in the following domain by assigning members of the domain to the constants used in the theory and sets of members of the domain to the predicates used in the theory. Domain = {Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune} -(∃x)(Ax • Bx) (∃x)(Ax • ∼Bx) (∀x)[Ax ⊃ (Bx \lor Cx)] (∃x)Ax ⊃ (∃x)(Ax • Bx)

(Essay)
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consider the following domain, assignment of objects in the domain, and assignments sets to predicates. Domain = {1, 2, 3, ..., 28, 29, 30} N = {1, 2, 3, ..., 28, 29, 30} E = {2, 4, 6, ..., 28, 30} O = {1, 3, 5, ..., 27, 29} P = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29} a = 1 b = 2 c = 28 -Given the customary truth tables, which of the following theories is modeled by the above interpretation?

(Multiple Choice)
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refer to the following formula: (∀x)[(Ex \lor Fx) ⊃ (Gx • Hd)] -What is the main operator of the given formula?

(Short Answer)
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select a counterexample for the given invalid argument. -1. (∃x)(Hx • Ix) 2) (∃x)(Hx • ∼Ix) 3) (∀x)(Jx ⊃ Ix) / (∀x)(Jx ⊃ Hx)

(Multiple Choice)
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