Exam 4: Monadic Predicate Logic

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select the best translation into predicate logic. -Either only cities are nicely placed or some settlements are not productive.

(Multiple Choice)
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use: b: Berkeley h: Hume Ax: x is an apriorist Cx: x is consistent Ex: x is an empiricist Ix: x is an idealist Px: x is a person Rx: x is a rationalist Sx: x is a skeptic Tx: x is a theist -If some idealists are not skeptics then not all theists are rationalists.

(Short Answer)
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1. (∀x)(Cx ⊃ Dx) 2. (∀x)(Ex ⊃ ∼Dx) -Which of the following propositions is an immediate (one-step) consequence in M of the given premises?

(Multiple Choice)
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refer to the following formula: (∃x)[Mx • (∼Nc \lor ∼Ox)] ≡ (Py • Pb) -Which is the main operator of the formula?

(Multiple Choice)
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determine whether the given argument is valid or invalid. If it is invalid, select a counterexample. -1. (∃x)[Ax • (Bx \lor Cx)] 2) (∀x)(Bx ⊃ ∼Cx) 3) (∃x)Bx 4) Ca / (∃x)(Ax • Cx)

(Multiple Choice)
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provide a conterexample in a finite domain to each given invalid argument. -1. (∃x)(∼Ax ≡ Cx) 2. (∃x)(Ax • Cx) 3. (∀x)(Bx ⊃ Ax) / (∀x)(Cx ⊃ Bx)

(Essay)
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1. (∀x)(Hx ⊃ ∼Jx) 2. (∀x)(Ix ⊃ Jx) 3. Ha • Ib -Which of the following propositions is an immediate (one-step) consequence in M of the given premises?

(Multiple Choice)
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use: b: Berkeley h: Hume Ax: x is an apriorist Cx: x is consistent Ex: x is an empiricist Ix: x is an idealist Px: x is a person Rx: x is a rationalist Sx: x is a skeptic Tx: x is a theist -No apriorist rationalists are skeptics, but Hume is.

(Short Answer)
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determine whether the given argument is valid or invalid. If it is valid, provide a derivation of the conclusion from the premises. If it is invalid, provide a counterexample. -1. (∀x)(Gx ⊃ Hx) 2. (∃x)(Gx • Ix) 3. (∃x)(Gx • Jx) 4. (∀x)(Jx ⊃ Hx) / (∃x)(Ix • Jx)

(Essay)
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1. (∀x)Ix ⊃ (∀x)Kx 2. (∀x)[Jx • (Ix \lor Lx)] 3. (∀x)(Jx ⊃ ∼Lx) -Which of the following propositions is derivable from the given premises in M?

(Multiple Choice)
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Translate each sentence into predicate logic, using the given translation keys. Ax: x is an athlete Dx: x has determination Px: x plays professional sports Sx: x receives a scholarship Tx: x is tall Wx: x works hard -Some athletes who don't work hard receive scholarships, if, and only if, no athletes who play professional sports don't have determination.

(Short Answer)
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derive the conclusions of each of the following arguments using the rules of inference for M. Do not use conditional or indirect proof. -1. (∃x)(Hx • ∼Ix) 2. (∀x)(Hx ⊃ Jx) 3. ∼(∃x)(Jx • Kx) / (∃x)∼(Ix \lor Kx)

(Essay)
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refer to the following formula: (∃x)[Mx • (∼Nc \lor ∼Ox)] ≡ (Py • Pb) -Which variables are bound by the '(∃x)'?

(Short Answer)
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use: b: Berkeley h: Hume Ax: x is an apriorist Cx: x is consistent Ex: x is an empiricist Ix: x is an idealist Px: x is a person Rx: x is a rationalist Sx: x is a skeptic Tx: x is a theist -Some apriorist is a skeptic if, and only if, s/he is an inconsistent empiricist.

(Short Answer)
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1. (∀x)(Fx ⊃ ∼Gx) 2. (∃x)(Hx • Gx) -Which of the following propositions is derivable from the given premises in M?

(Multiple Choice)
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1. (∃x)Qx ⊃ (∀x)(Rx ⊃ Sx) 2. (∀x)∼Qx ⊃ (∃x)Sx 3. (∀x)Rx / (∃x)Sx -Which of the following propositions is an appropriate assumption for an indirect proof of the conclusion of the given argument?

(Multiple Choice)
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refer to the following formula: ∼(∀x){(Ix • Jx) ⊃ [Kx ≡ (La • Lb)]} -List all of the subformulas in the scope of '(∀x)'.

(Short Answer)
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construct theories for which the following interpretation is a model (i.e. construct at least two sentences which are true under the given interpretation). Domain = {1, 2, 3, ..., 28, 29, 30} E = {2, 4, 6, ..., 28, 30} O = {1, 3, 5, ..., 27, 29} P = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29} a = 1 d = 19 b = 2 e = 23 c = 3 f = 29 -Construct a theory of at least two sentences, at least one of which uses a universal quantifier.

(Essay)
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refer to the following formula: (∃x)[(Ax • ∼Bx) • ∼(Cx \lor Dx)] -What is the main operator of the given formula?

(Short Answer)
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determine whether the given formula is a logical truth of M or not. If it is not a logical truth, select a false valuation. -[(∃x)Ex • (∃x)∼Ex)] ⊃ (∀x)(Ex \lor ∼Ex)

(Multiple Choice)
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