Exam 20: Exponential and Logarithmic Functions

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Solve for x:(2x+3)(3x+2)=9(24x)x:\left(2^{x+3}\right)\left(3^{x+2}\right)=9\left(24^{x}\right)

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Solve for x:e4x3=2e2x+1x: e^{4 x-3}=2 e^{2 x+1}

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Graph the exponential function over the given domain of xx . y=44ex(x=0y=4-4 e^{-x}(x=0 to 4 ))

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In a certain chemical reaction the concentration of a certain product molecule CC is given by C=2(1e0.13t)C=2\left(1-e^{-0.13 t}\right) moles/liter, where tt is the time the reaction has been running in seconds. Find CC after the reaction has run for eleven seconds.

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Simplify: 102logx10^{2 \log x}

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Solve for x:3x+1+32x=12x: 3^{x+1}+3^{2-x}=12

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Convert to exponential form: log5x=3y\log _{5} x=3 y

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A person has $25,000\$ 25,000 is invested in an account that pays 6%6 \% interest per year, compounded monthly. What is the value of the account after ten years?

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Solve for xx to three significant digits: ln(2x+5)ln(6x+1)=ln(6)\ln (2 x+5)-\ln (6 x+1)=\ln (6)

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Solve for x:81x12812x+27=0x: \sqrt[x]{81}-12 \sqrt[2 x]{81}+27=0

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A certain company comes out with a new product and the number of investors in the company grows exponentially at a rate of 10%10 \% per week. After three weeks, there are 1,290 investors in the company. How many investors were there before the three weeks?

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Solve for xx , to three significant digits: 24x+22x=1322^{4 x}+2^{2 x}=132

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If the power input is P1P_{1} and the power output is P2P_{2} , the number of decibels gained or lost is G=10logP2P1G=10 \log \frac{P_{2}}{P_{1}} (dB). If the amplifier gains 15.0 dB15.0 \mathrm{~dB} for an input of 90.0 W90.0 \mathrm{~W} , find the power output.

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Find the common logarithm of each number to four decimal places: (a) 0.5 (b) 12.75 (c) 291 (d) 0.0132

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Convert to logarithmic form: eπt=ve^{\pi t}=v

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Solve for x:logx(x22x+4)=2x: \log _{x}\left(x^{2}-2 x+4\right)=2

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Solve for x:2x+23x=6x: 2^{x}+2^{3-x}=6

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Rewrite the following equation so that it contains no logarithms: log(x+y)+log2=log(x2y2)\log (x+y)+\log 2=\log \left(x^{2}-y^{2}\right)

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How many years does a person need to leave $8000\$ 8000 in an account that pays 6.5%6.5 \% interest per year, compounded annually, to end up with $13,240\$ 13,240 ?

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Simplify: e3lnxe^{-3 \ln x}

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