Question 1

When testing for differences between treatment means,the t-statistic is based on ________.

Accepted Answer

A) the treatment degrees of freedom 
B) the total degrees of freedom 
C) the error degrees of freedom 
D) the ratio of treatment and error degrees of freedom 
A) the treatment degrees of freedom 
B) the total degrees of freedom 
C) the error degrees of freedom 
D) the ratio of treatment and error degrees of freedom C

Question 2

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results:   What is the critical value of F at the 0.02 level of significance?

Accepted Answer

A) 5.85 
B) 5.35 
C) 6.51 
D) 4.03 
A) 5.85 
B) 5.35 
C) 6.51 
D) 4.03 B

Question 3

One characteristic of the F-distribution is that the computed F can only range between -1 and +1.

Accepted Answer

A) True 
 B)False  False

Question 4

For the hypothesis test,H0: σ12= σ22,with n1 = 10 and n2 = 10,the F-test statistic is 2.56. At the 0.02 level of significance,we would reject the null hypothesis.

Accepted Answer

A) True 
 B)False

Question 5

ANOVA is a statistical approach used to determine whether or not ________.

Accepted Answer

A) the means of two or more samples are equal 
B) the means of two samples are equal 
C) the means of two or more populations are equal 
D) the means of more than two samples are equal 
A) the means of two or more samples are equal 
B) the means of two samples are equal 
C) the means of two or more populations are equal 
D) the means of more than two samples are equal

Question 6

If we want to determine which treatment means differ,we compute a confidence interval for the difference between each pair of means.

Accepted Answer

A) True 
 B)False

Question 7

Analysis of variance is used to ________.

Accepted Answer

A) compare nominal data 
B) compute a test 
C) compare population proportions 
D) simultaneously compare several population means 
A) compare nominal data 
B) compute a test 
C) compare population proportions 
D) simultaneously compare several population means

Question 8

For an ANOVA test,rejecting the null hypothesis does not identify which treatment means differ significantly.

Accepted Answer

A) True 
 B)False

Question 9

If there are five levels of Factor A and seven levels of Factor B for an ANOVA with interaction,what are the interaction degrees of freedom?

Accepted Answer

A) 12 
B) 35 
C) 24 
D) 10 
A) 12 
B) 35 
C) 24 
D) 10

Question 10

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow.   What is the treatment variable?

Accepted Answer

A) Day 
B) Class time 
C) Tuesday 
D) 8:00 am class 
A) Day 
B) Class time 
C) Tuesday 
D) 8:00 am class

Question 11

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results:   The calculated F ratio is ________.

Accepted Answer

A) 3.484 
B) 1.867 
C) 3.18 
D) 5.35 
A) 3.484 
B) 1.867 
C) 3.18 
D) 5.35

Question 12

A manufacturer of automobile transmissions uses three different processes. Management ordered a study of the production costs to see if there is a difference among the three processes. A summary of the findings is shown next.   In an ANOVA table,what are the degrees of freedom for the treatment source of variation?

Accepted Answer

A) 2 
B) 3 
C) 10 
D) 27 
A) 2 
B) 3 
C) 10 
D) 27

Question 13

If a confidence interval for the difference between a pair of treatment means includes 0,then we reject the null hypothesis that there is no difference in the pair of treatment means.

Accepted Answer

A) True 
 B)False

Question 14

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results:   At the 2% level of significance,what is the decision?

Accepted Answer

A) Reject the null hypothesis and conclude the variances are different. 
B) Fail to reject the null hypothesis and conclude the variances are different. 
C) Reject the null hypothesis and conclude the variances are the same. 
D) Fail to reject the null hypothesis and conclude the variances are the same. 
A) Reject the null hypothesis and conclude the variances are different. 
B) Fail to reject the null hypothesis and conclude the variances are different. 
C) Reject the null hypothesis and conclude the variances are the same. 
D) Fail to reject the null hypothesis and conclude the variances are the same.

Question 15

The annual dividend rates for a random sample of 16 companies in three different industries,utilities,banking,and insurance,were recorded. The ANOVA comparing the mean annual dividend rate among three industries rejected the null hypothesis that the dividend rates were equal. The mean square error (MSE)was 3.36. The following table summarized the results:   Based on the comparison between the mean annual dividend rate for companies in utilities and banking,the 95% confidence interval shows an interval of 1.28 to 6.28 for the difference. This result indicates that ________.

Accepted Answer

A) there is no significant difference between the two rates 
B) the interval contains a difference of 5.00 
C) the annual dividend rate in the utilities industry is significantly less than the annual dividend rate in the banking industry 
D) the annual dividend rate in the banking industry is significantly less than the annual dividend rate in the utilities industry 
A) there is no significant difference between the two rates 
B) the interval contains a difference of 5.00 
C) the annual dividend rate in the utilities industry is significantly less than the annual dividend rate in the banking industry 
D) the annual dividend rate in the banking industry is significantly less than the annual dividend rate in the utilities industry

Question 16

An ANOVA procedure is applied to data obtained from four distinct populations. The samples,each comprised of 15 observations,were taken from the four populations. The degrees of freedom for the numerator and denominator for the critical value of are ________.

Accepted Answer

A) 4 and 60,respectively 
B) 4 and 21,respectively 
C) 3 and 59,respectively 
D) 3 and 56,respectively 
A) 4 and 60,respectively 
B) 4 and 21,respectively 
C) 3 and 59,respectively 
D) 3 and 56,respectively

Question 17

A random sample of 40 companies with assets over $10 million was surveyed and asked to indicate their industry and annual computer technology expense. The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis. The mean square error (MSE)was 195. The following table summarized the results:   Based on the comparison between the mean annual computer technology expense for companies in the tax service and food service industries,the 95% confidence interval shows an interval of −5.85 to 14.85 for the difference. This result indicates that ________.

Accepted Answer

A) there is not enough evidence of a significant difference between the two industry technology expenses 
B) the interval contains a difference of 20.7 
C) companies in the food service industry spend significantly more than companies in the tax service industry 
D) companies in the food service industry spend significantly less than companies in the tax service industry 
A) there is not enough evidence of a significant difference between the two industry technology expenses 
B) the interval contains a difference of 20.7 
C) companies in the food service industry spend significantly more than companies in the tax service industry 
D) companies in the food service industry spend significantly less than companies in the tax service industry

Question 18

The null hypothesis for an ANOVA analysis comparing four treatment means is rejected. The four sample means are   = 10,   = 12,   = 15,   = 18. The sample size for each treatment is the same. If (   -   )is significantly different from zero,then ________.

Accepted Answer

A)    is significantly less than   ,   ,   . 
B)    is significantly less than   and   . 
C)    and   are significantly different 
D) the treatment means are all equal 
A)    is significantly less than   ,   ,   . 
B)    is significantly less than   and   . 
C)    and   are significantly different 
D) the treatment means are all equal

Question 19

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow.   What is the critical statistic for testing the hypothesis of equal treatment means at the 0.05 significance level?

Accepted Answer

A) 1.96 
B) 6.94 
C) 3.84 
D) 4.46 
A) 1.96 
B) 6.94 
C) 3.84 
D) 4.46

Question 20

An electronics company wants to compare the quality of their cell phones to the cell phones from three competitors. They sample 10 phones from each company and count the number of defects for each phone. If ANOVA was used to compare the average number of defects,then the treatments would be defined as ________.

Accepted Answer

A) the number of cell phones sampled 
B) the average number of defects 
C) the total number of phones 
D) the four companies 
A) the number of cell phones sampled 
B) the average number of defects 
C) the total number of phones 
D) the four companies

When testing for differences between treatment means,the t-statistic is based on ________.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: What is the critical value of F at the 0.02 level of significance?

One characteristic of the F-distribution is that the computed F can only range between -1 and +1.

For the hypothesis test,H₀: σ₁²= σ₂²,with n₁ = 10 and n₂ = 10,the F-test statistic is 2.56. At the 0.02 level of significance,we would reject the null hypothesis.

ANOVA is a statistical approach used to determine whether or not ________.

If we want to determine which treatment means differ,we compute a confidence interval for the difference between each pair of means.

Analysis of variance is used to ________.

For an ANOVA test,rejecting the null hypothesis does not identify which treatment means differ significantly.

If there are five levels of Factor A and seven levels of Factor B for an ANOVA with interaction,what are the interaction degrees of freedom?

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow. What is the treatment variable?

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: The calculated F ratio is ________.

If a confidence interval for the difference between a pair of treatment means includes 0,then we reject the null hypothesis that there is no difference in the pair of treatment means.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: At the 2% level of significance,what is the decision?

An ANOVA procedure is applied to data obtained from four distinct populations. The samples,each comprised of 15 observations,were taken from the four populations. The degrees of freedom for the numerator and denominator for the critical value of are ________.

The null hypothesis for an ANOVA analysis comparing four treatment means is rejected. The four sample means are = 10, = 12, = 15, = 18. The sample size for each treatment is the same. If ( - )is significantly different from zero,then ________.

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow. What is the critical statistic for testing the hypothesis of equal treatment means at the 0.05 significance level?

What Is Statistics

Describing Data: Frequency Tables, Frequency Distributions, and Graphic Presentation

Describing Data: Numerical Measures

Describing Data: Displaying and Exploring Data

A Survey of Probability Concepts

Discrete Probability Distributions

Continuous Probability Distributions

Sampling Methods and the Central Limit Theorem

Estimation and Confidence Intervals

One-Sample Tests of Hypothesis

Two-Sample Tests of Hypothesis

Correlation and Linear Regression

Multiple Regression Analysis

Nonparametric Methods: Nominal Level Hypothesis Tests

Nonparametric Methods: Analysis of Ordinal Data

Index Numbers

Time Series and Forecasting

Statistical Process Control and Quality Management

An Introduction to Decision Theory

Filters

Exam 12: Analysis of Variance

When testing for differences between treatment means,the t-statistic is based on ________.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: What is the critical value of F at the 0.02 level of significance?

One characteristic of the F-distribution is that the computed F can only range between -1 and +1.

For the hypothesis test,H0: σ12= σ22,with n1 = 10 and n2 = 10,the F-test statistic is 2.56. At the 0.02 level of significance,we would reject the null hypothesis.

ANOVA is a statistical approach used to determine whether or not ________.

If we want to determine which treatment means differ,we compute a confidence interval for the difference between each pair of means.

Analysis of variance is used to ________.

For an ANOVA test,rejecting the null hypothesis does not identify which treatment means differ significantly.

If there are five levels of Factor A and seven levels of Factor B for an ANOVA with interaction,what are the interaction degrees of freedom?

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow. What is the treatment variable?

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: The calculated F ratio is ________.

If a confidence interval for the difference between a pair of treatment means includes 0,then we reject the null hypothesis that there is no difference in the pair of treatment means.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this,they each graded the same 10 exams,with the following results: At the 2% level of significance,what is the decision?

An ANOVA procedure is applied to data obtained from four distinct populations. The samples,each comprised of 15 observations,were taken from the four populations. The degrees of freedom for the numerator and denominator for the critical value of are ________.

The null hypothesis for an ANOVA analysis comparing four treatment means is rejected. The four sample means are = 10, = 12, = 15, = 18. The sample size for each treatment is the same. If ( - )is significantly different from zero,then ________.

The college of business was interested in comparing the attendance for three different class times for a business statistics class. The data follow. What is the critical statistic for testing the hypothesis of equal treatment means at the 0.05 significance level?

What Is Statistics

Describing Data: Frequency Tables, Frequency Distributions, and Graphic Presentation

Describing Data: Numerical Measures

Describing Data: Displaying and Exploring Data

A Survey of Probability Concepts

Discrete Probability Distributions

Continuous Probability Distributions

Sampling Methods and the Central Limit Theorem

Estimation and Confidence Intervals

One-Sample Tests of Hypothesis

Two-Sample Tests of Hypothesis

Correlation and Linear Regression

Multiple Regression Analysis

Nonparametric Methods: Nominal Level Hypothesis Tests

Nonparametric Methods: Analysis of Ordinal Data

Index Numbers

Time Series and Forecasting

Statistical Process Control and Quality Management

An Introduction to Decision Theory

Filters

For the hypothesis test,H₀: σ₁²= σ₂²,with n₁ = 10 and n₂ = 10,the F-test statistic is 2.56. At the 0.02 level of significance,we would reject the null hypothesis.