Exam 7: Continuous Probability Distributions

A company employs 300 employees. Each year, there is a 30 percent turnover rate for employees. We want to do a normal approximation to the binomial distribution of the number of employees who leave each year. For this normal approximation, the mean is __ and the standard deviation is _.

(Multiple Choice)

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Question 21

The triangular distribution T(10, 20, 50) has a standard deviation of:

(Multiple Choice)

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Question 22

The exponential distribution describes the number of arrivals per unit of time.

(True/False)

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Question 23

Assume that X is normally distributed with a mean μ = $64. Given that P(X ≥ $75) = 0.2981, we can calculate that the standard deviation of X is approximately:

(Multiple Choice)

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Question 24

The MPG (miles per gallon) for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. What is the probability that the MPG for a randomly selected compact car would be less than 32?

(Multiple Choice)

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Question 25

If arrivals occur at a mean rate of 1.6 events per minute, the exponential probability of waiting less than 1 minute for the next arrival is:

(Multiple Choice)

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Question 26

A continuous uniform distribution U(0, 800) will have μ = 400 and σ = 230.94.

(True/False)

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Question 27

The true proportion of accounts receivable with some kind of error is 4 percent for Venal Enterprises. If an auditor randomly samples 50 accounts receivable, it is acceptable to use the normal approximation to estimate the probability that fewer than two will contain errors.

(True/False)

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Question 28

The mean, median, and mode of a normal distribution will always be the same.

(True/False)

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Question 29

If the mean waiting time for the next arrival is 12 minutes, what is the median waiting time?

(Multiple Choice)

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Question 30

Regarding continuous probability distributions, which statement is incorrect?

(Multiple Choice)

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Question 31

On average, 15 minutes elapse between discoveries of fraudulent corporate tax returns in a certain IRS office. What is the probability that less than 30 minutes will elapse before the next fraudulent corporate tax return is discovered?

(Multiple Choice)

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Question 32

Exam scores were normal in MIS 200. Jason's exam score was 1.41 standard deviations above the mean. What percentile is he in?

(Multiple Choice)

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Question 33

Which probability model is most appropriate to describe the waiting time (working days) until an office photocopier breaks down (i.e., requires unscheduled maintenance)?

(Multiple Choice)

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Question 34

The figure shows a standard normal N(0, 1) distribution. Find the z value for the shaded area. C.2 gives P(z < -2.17) = .0150 or use Excel =NORM.S.INV(0.015) = -2.17.

(Multiple Choice)

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Question 35

The exponential distribution is continuous and the Poisson distribution is discrete, yet the two distributions are closely related.

(True/False)

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Question 36

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z > 1.75) = .0401, so x = µ + zσ = 400 + 1.75(23) = 440.3, or from Excel =NORM.INV(0.96,400,23) = 440.3.

(Multiple Choice)

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Question 37

In Melanie's Styling Salon, the time to complete a simple haircut is normally distributed with a mean of 25 minutes and a standard deviation of 4 minutes. What percentage of customers require less than 32 minutes for a simple haircut?

(Multiple Choice)

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Question 38

The probability is .80 that a standard normal random variable is between -z and +z. The value of z is approximately:

(Multiple Choice)

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Question 39

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z < -1.645) = .05, so x = µ + zσ = 400 - 1.645(23) = 362.2, or from Excel =NORM.INV(0.05,400,23) = 362.2.

(Multiple Choice)

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Question 40

Showing 21 - 40 of 120

A company employs 300 employees. Each year, there is a 30 percent turnover rate for employees. We want to do a normal approximation to the binomial distribution of the number of employees who leave each year. For this normal approximation, the mean is __ and the standard deviation is _.

The triangular distribution T(10, 20, 50) has a standard deviation of:

The exponential distribution describes the number of arrivals per unit of time.

Assume that X is normally distributed with a mean μ = $64. Given that P(X ≥ $75) = 0.2981, we can calculate that the standard deviation of X is approximately:

The MPG (miles per gallon) for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. What is the probability that the MPG for a randomly selected compact car would be less than 32?

If arrivals occur at a mean rate of 1.6 events per minute, the exponential probability of waiting less than 1 minute for the next arrival is:

A continuous uniform distribution U(0, 800) will have μ = 400 and σ = 230.94.

The true proportion of accounts receivable with some kind of error is 4 percent for Venal Enterprises. If an auditor randomly samples 50 accounts receivable, it is acceptable to use the normal approximation to estimate the probability that fewer than two will contain errors.

The mean, median, and mode of a normal distribution will always be the same.

If the mean waiting time for the next arrival is 12 minutes, what is the median waiting time?

Regarding continuous probability distributions, which statement is incorrect?

On average, 15 minutes elapse between discoveries of fraudulent corporate tax returns in a certain IRS office. What is the probability that less than 30 minutes will elapse before the next fraudulent corporate tax return is discovered?

Exam scores were normal in MIS 200. Jason's exam score was 1.41 standard deviations above the mean. What percentile is he in?

Which probability model is most appropriate to describe the waiting time (working days) until an office photocopier breaks down (i.e., requires unscheduled maintenance)?

The figure shows a standard normal N(0, 1) distribution. Find the z value for the shaded area. C.2 gives P(z < -2.17) = .0150 or use Excel =NORM.S.INV(0.015) = -2.17.

The exponential distribution is continuous and the Poisson distribution is discrete, yet the two distributions are closely related.

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z > 1.75) = .0401, so x = µ + zσ = 400 + 1.75(23) = 440.3, or from Excel =NORM.INV(0.96,400,23) = 440.3.

In Melanie's Styling Salon, the time to complete a simple haircut is normally distributed with a mean of 25 minutes and a standard deviation of 4 minutes. What percentage of customers require less than 32 minutes for a simple haircut?

The probability is .80 that a standard normal random variable is between -z and +z. The value of z is approximately:

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z < -1.645) = .05, so x = µ + zσ = 400 - 1.645(23) = 362.2, or from Excel =NORM.INV(0.05,400,23) = 362.2.

Overview of Statistics

Data Collection

Describing Data Visually

Descriptive Statistics

Probability

Discrete Probability Distributions

Sampling Distributions and Estimation

One-Sample Hypothesis Tests

Two-Sample Hypothesis Tests

Analysis of Variance

Simple Regression

Multiple Regression

Time Series Analysis

Chi-Square Tests

Nonparametric Tests

Quality Management

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Exam 7: Continuous Probability Distributions

A company employs 300 employees. Each year, there is a 30 percent turnover rate for employees. We want to do a normal approximation to the binomial distribution of the number of employees who leave each year. For this normal approximation, the mean is ______ and the standard deviation is _____.

The triangular distribution T(10, 20, 50) has a standard deviation of:

The exponential distribution describes the number of arrivals per unit of time.

Assume that X is normally distributed with a mean μ = $64. Given that P(X ≥ $75) = 0.2981, we can calculate that the standard deviation of X is approximately:

The MPG (miles per gallon) for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. What is the probability that the MPG for a randomly selected compact car would be less than 32?

If arrivals occur at a mean rate of 1.6 events per minute, the exponential probability of waiting less than 1 minute for the next arrival is:

A continuous uniform distribution U(0, 800) will have μ = 400 and σ = 230.94.

The true proportion of accounts receivable with some kind of error is 4 percent for Venal Enterprises. If an auditor randomly samples 50 accounts receivable, it is acceptable to use the normal approximation to estimate the probability that fewer than two will contain errors.

The mean, median, and mode of a normal distribution will always be the same.

If the mean waiting time for the next arrival is 12 minutes, what is the median waiting time?

Regarding continuous probability distributions, which statement is incorrect?

On average, 15 minutes elapse between discoveries of fraudulent corporate tax returns in a certain IRS office. What is the probability that less than 30 minutes will elapse before the next fraudulent corporate tax return is discovered?

Exam scores were normal in MIS 200. Jason's exam score was 1.41 standard deviations above the mean. What percentile is he in?

Which probability model is most appropriate to describe the waiting time (working days) until an office photocopier breaks down (i.e., requires unscheduled maintenance)?

The figure shows a standard normal N(0, 1) distribution. Find the z value for the shaded area. C.2 gives P(z < -2.17) = .0150 or use Excel =NORM.S.INV(0.015) = -2.17.

The exponential distribution is continuous and the Poisson distribution is discrete, yet the two distributions are closely related.

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z > 1.75) = .0401, so x = µ + zσ = 400 + 1.75(23) = 440.3, or from Excel =NORM.INV(0.96,400,23) = 440.3.

In Melanie's Styling Salon, the time to complete a simple haircut is normally distributed with a mean of 25 minutes and a standard deviation of 4 minutes. What percentage of customers require less than 32 minutes for a simple haircut?

The probability is .80 that a standard normal random variable is between -z and +z. The value of z is approximately:

The figure shows a normal N(400, 23) distribution. Find the x value for the shaded area. C.2 we get P(z < -1.645) = .05, so x = µ + zσ = 400 - 1.645(23) = 362.2, or from Excel =NORM.INV(0.05,400,23) = 362.2.

Overview of Statistics

Data Collection

Describing Data Visually

Descriptive Statistics

Probability

Discrete Probability Distributions

Sampling Distributions and Estimation

One-Sample Hypothesis Tests

Two-Sample Hypothesis Tests

Analysis of Variance

Simple Regression

Multiple Regression

Time Series Analysis

Chi-Square Tests

Nonparametric Tests

Quality Management

Filters

A company employs 300 employees. Each year, there is a 30 percent turnover rate for employees. We want to do a normal approximation to the binomial distribution of the number of employees who leave each year. For this normal approximation, the mean is __ and the standard deviation is _.