Exam 23: Photon Dosimetry Concepts and Calculations

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Using the 6-MV PDD chart, what is the dose at 10 cm if the dose at Dmax is 300 cGy per day on a 6-MV beam for a field size of 15 × 18?

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Absorbed dose at depth × 100% = absorbed dose at Dmax is the definition of which of the following?

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As the energy increases, what happens to the PDD?

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The intensity of a radiation beam is measured at 10 mR/hr at a distance of 20 cm.What will be the intensity of this beam at 30 cm?

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Which of the following are adjacent fields that match on the surface and have an overlap at depth due to divergence?

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A patient is being treated on the 18-MV beam to a PA spine at a depth of 10 cm.The collimator setting is 10 × 13 with no blocks.The dose is 300 cGy per fraction.What is the dose delivered to Dmax?

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A patient is treated using two superiorly/inferiorly adjacent fields.The collimator setting for the superior field is 10 cm wide by 13 cm long.The collimator setting for the inferior field is 20 cm wide by 35 cm long.Both fields are treated at 100 cm SSD.Calculate the gap at the skin surface if the fields abut at a depth of 5 cm.

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The intensity of a radioactive beam is measured at a distance of 100 cm and found to be 250 mR/min.What will the intensity of this beam be at 105 cm?

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What is the patient separation if depth from the anterior posterior (AP)is 9 cm and depth from posterior anterior (PA)is 11 cm?

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A patient is being treated on the 18-MV beam to an AP/PA stomach (midline).The collimator setting is 12 × 12 with no blocks.The dose is 4400 cGy/22 fractions.The separation is 24 cm.The cord is 4 cm from the PA.What dose is delivered to the spinal cord?

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The physician prescribes the AP/PA field to be weighted 3:1 for the posterior field.How much dose is coming from the AP and the PA if total dose prescribed is 200 cGy?

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What is the depth from the PA if the SAD is 100 cm and the SSD is 89 cm?

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Mayneord F factor is used in which of the following?

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Which of the following defines Dmax?

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A patient is being treated on the 6-MV beam to an opposed lateral whole brain (midline).The collimator setting is 14 × 18 with no blocks.The dose is 4000 cGy/20 fractions.The separation is 22 cm.What is the dose delivered to Dmax?

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Find the skin gap necessary to match two symmetric ports at midline that are 21 and 37 cm in length.Assume the midline depth is 13 cm and both ports are treated at 100 cm SAD.

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Calculate the PDD of depth (d)if the dose at Dmax is 250 cGy and the dose at d is 231 cGy.

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A patient is treated on a 6-MV machine at 100 cm SSD.The collimator setting is 15 × 15.There is no blocking used for this treatment.The prescription states that a dose of 3000 cGy is to be delivered to a depth of 3 cm in 10 fractions using a posterior treatment field using the nonisocentric method of calculation.The patient central axis separation is 20 cm.What is the MU setting for the treatment? Reference dose rate (RDR)for a 15 cm equivalent square is 0.993 cGy/MU.

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Which of the following is the equivalent square of rectangular field of 10 ´ 15?

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