Exam 15: Oscillations
Exam 1: Measurement37 Questions
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Exam 4: Motion in Two and Three Dimensions56 Questions
Exam 5: Force and Motion I73 Questions
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Exam 7: Kinetic Energy and Work73 Questions
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Exam 9: Center of Mass and Linear Momentum99 Questions
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Exam 11: Rolling, Torque, and Angular Momentum66 Questions
Exam 12: Equilibrium and Elasticity57 Questions
Exam 13: Gravitation55 Questions
Exam 14: Fluids88 Questions
Exam 15: Oscillations75 Questions
Exam 16: Waves I82 Questions
Exam 17: Waves II71 Questions
Exam 18: Temperature, Heat, and the First Law of Thermodynamics96 Questions
Exam 19: The Kinetic Theory of Gases113 Questions
Exam 20: Entropy and the Second Law of Thermodynamics61 Questions
Exam 21: Electric Charge52 Questions
Exam 22: Electric Fields55 Questions
Exam 23: Gauss Law38 Questions
Exam 24: Electric Potential52 Questions
Exam 25: Capacitance61 Questions
Exam 26: Current and Resistance55 Questions
Exam 27: Circuits73 Questions
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Exam 30: Induction and Inductance90 Questions
Exam 31: Electromagnetic Oscillations and Alternating Current88 Questions
Exam 32: Maxwells Equations; Magnetism of Matter81 Questions
Exam 33: Electromagnetic Waves83 Questions
Exam 34: Images79 Questions
Exam 35: Interference46 Questions
Exam 36: Diffraction77 Questions
Exam 37: Relativity68 Questions
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Exam 39: More About Matter Waves41 Questions
Exam 40: All About Atoms79 Questions
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Exam 42: Nuclear Physics68 Questions
Exam 43: Energy From the Nucleus50 Questions
Exam 44: Quarks, Leptons, and the Big Bang55 Questions
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Five particles undergo damped harmonic motion. Values for the spring constant k, the damping constant b, and the mass m are given below. Which leads to the smallest rate of loss of mechanical energy?
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(Multiple Choice)
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Correct Answer:
B
A particle moves in simple harmonic motion according to x = 2cos(50t), where x is in meters and t is in seconds. Its maximum velocity is:
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Correct Answer:
C
A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the system has an energy of 6.0 J, then the amplitude of the oscillation is:
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The angular displacement of a simple pendulum is given by θ(t) = θm cos (ωt + φ). If the pendulum is 45 cm in length, and is given an angular speed dθ/dt = 3.4 rad/s at time t = 0, when it is hanging vertically, what is θm?
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A 0.20-kg object mass attached to a spring whose spring constant is 500 N/m executes simple harmonic motion. If its maximum speed is 5.0 m/s, the amplitude of its oscillation is:
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An object is undergoing simple harmonic motion. Throughout a complete cycle it:
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It is impossible for two particles, each executing simple harmonic motion, to remain in phase with each other if they have different:
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A particle is in simple harmonic motion with period T. At time t=0 it is halfway between the equilibrium point and an end point of its motion, travelling toward the end point. The next time it is at the same place is:
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A block attached to a spring oscillates in simple harmonic motion along the x axis. The limits of its motion are x = 10 cm and x = 50 cm and it goes from one of these extremes to the other in 0.25 s. Its amplitude and frequency are:
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For an oscillator subjected to a damping force proportional to its velocity:
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The displacement of an object oscillating on a spring is given by x(t) = xmcos( t + ). If the initial displacement is zero and the initial velocity is in the negative x direction, then the phase constant is:
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A sinusoidal force with a given amplitude is applied to an oscillator. To maintain the largest amplitude oscillation the frequency of the applied force should be:
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The amplitude of oscillation of a simple pendulum is increased from 1 to 4 . Its maximum acceleration changes by a factor of:
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In simple harmonic motion, the restoring force must be proportional to the:
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A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the oscillation is started by elongating the spring 0.15 m and giving the block a speed of 3.0 m/s, then the amplitude of the oscillation is:
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An angular simple harmonic oscillator is displaced 5.2 x 10-2 rad from its equilibrium position. If the torsion constant is 1200 N∙m/rad, what is the torque?
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