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When 020 Mole HF Is Dissolved in Water to a Volume

Question 23

Multiple Choice

When 0.20 mole HF is dissolved in water to a volume of 1.00 L,5.8% of the HF dissociates to form F-(aq) .What is the equilibrium constant for the reaction? HF(aq) + H2O( When 0.20 mole HF is dissolved in water to a volume of 1.00 L,5.8% of the HF dissociates to form F<sup>-</sup>(aq) .What is the equilibrium constant for the reaction? HF(aq) + H<sub>2</sub>O( ) F<sup>-</sup>(aq) + H<sub>3</sub>O<sup>+</sup>(aq) A) 1.3 × 10<sup>-4</sup> B) 7.1 × 10<sup>-4</sup> C) 1.2 × 10<sup>-2</sup> D) 1.7 × 10<sup>-2</sup> E) 6.2 × 10<sup>-2</sup> ) When 0.20 mole HF is dissolved in water to a volume of 1.00 L,5.8% of the HF dissociates to form F<sup>-</sup>(aq) .What is the equilibrium constant for the reaction? HF(aq) + H<sub>2</sub>O( ) F<sup>-</sup>(aq) + H<sub>3</sub>O<sup>+</sup>(aq) A) 1.3 × 10<sup>-4</sup> B) 7.1 × 10<sup>-4</sup> C) 1.2 × 10<sup>-2</sup> D) 1.7 × 10<sup>-2</sup> E) 6.2 × 10<sup>-2</sup> F-(aq) + H3O+(aq)


A) 1.3 × 10-4
B) 7.1 × 10-4
C) 1.2 × 10-2
D) 1.7 × 10-2
E) 6.2 × 10-2

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