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Find the Derivative of the Function t(x)=cotx4+8secxt ( x ) = \frac { \cot x } { 4 + 8 \sec x }

Question 67

Multiple Choice

Find the derivative of the function. t(x) =cotx4+8secxt ( x ) = \frac { \cot x } { 4 + 8 \sec x }


A) t(x) =(48secx) csc2x+8secx(48secx) 2t ^ { \prime } ( x ) = - \frac { ( 4 - 8 \sec x ) \csc ^ { 2 } x + 8 \sec x } { ( 4 - 8 \sec x ) ^ { 2 } }
B) t(x) =(4+8secx) csc2x+8secx(4+8secx) 2t ^ { \prime } ( x ) = - \frac { ( 4 + 8 \sec x ) \csc ^ { 2 } x + 8 \sec x } { ( 4 + 8 \sec x ) ^ { 2 } }
C) t(x) =(4+8secx) csc2x+8secx(4+8secx) 2t ^ { \prime } ( x ) = \frac { ( 4 + 8 \sec x ) \csc ^ { 2 } x + 8 \sec x } { ( 4 + 8 \sec x ) ^ { 2 } }
D) t(x) =(4+8secx) csc2x+8secx(48secx) 2t ^ { \prime } ( x ) = - \frac { ( 4 + 8 \sec x ) \csc ^ { 2 } x + 8 \sec x } { ( 4 - 8 \sec x ) ^ { 2 } }
E) t(x) =(48secx) csc2x8secx(48secx) 2t ^ { \prime } ( x ) = - \frac { ( 4 - 8 \sec x ) \csc ^ { 2 } x - 8 \sec x } { ( 4 - 8 \sec x ) ^ { 2 } }

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