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Find the Equation of the Line Tangent to the Graph x=1x = 1

Question 25

Multiple Choice

Find the equation of the line tangent to the graph of the given function at the point x=1x = 1 . f(x) =(x3+3) (x2+x) f ( x ) = \left( x ^ { 3 } + 3 \right) \left( x ^ { 2 } + x \right)


A) y=8y = 8
B) y=18x10y = 18 x - 10
C) y=8xy = 8 x
D) y=18y = 18
E) y=18xy = 18 x

Correct Answer:

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