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If f(x)=x2+4f(x)=\frac{x}{2}+4 And G(x)= X + 1, How Do ∫812f(x)dx\int_{8}^{12} f(x) d x

Question 1

Multiple Choice

If f(x) =x2+4f(x) =\frac{x}{2}+4 and g(x) = x + 1, how do ∫812f(x) dx\int_{8}^{12} f(x) d x and ∫812g(x) dx\int_{8}^{12} g(x) d x compare?


A) ∫812f(x) dx\int_{8}^{12} f(x) d x < ∫812g(x) dx\int_{8}^{12} g(x) d x
B) ∫812f(x) dx\int_{8}^{12} f(x) d x > ∫812g(x) dx\int_{8}^{12} g(x) d x
C) ∫812f(x) dx\int_{8}^{12} f(x) d x = ∫812g(x) dx\int_{8}^{12} g(x) d x

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