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Solve the Initial Value Problem dydt+7y=3;y(0)=1\frac { d y } { d t } + 7 y = 3 ; y ( 0 ) = 1

Question 40

Multiple Choice

Solve the initial value problem.
- dydt+7y=3;y(0) =1\frac { d y } { d t } + 7 y = 3 ; y ( 0 ) = 1


A) y=37e7t+47y = \frac { 3 } { 7 } e ^ { - 7 t } + \frac { 4 } { 7 }
B) y=47e7t+37y = \frac { 4 } { 7 } e ^ { 7 t } + \frac { 3 } { 7 }
C) y=47e7t+37y = \frac { 4 } { 7 } e ^ { - 7 t } + \frac { 3 } { 7 }
D) y=37e7t+47y = \frac { 3 } { 7 } e ^ { 7 t } + \frac { 4 } { 7 }

Correct Answer:

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